[英]How to get the count of most frequent pattern in elasticsearch?
我想通过elasticsearch
获得十种最常见的搜索模式。
范例:
"cgn:4189, dfsdkfldslfs"
"cgn:4210, aezfvdsvgds"
"cgn:4189, fdsmpfjdjs"
"cgn:4195, cvsf"
"cgn:4189, mkpjd"
"cgn:4210, mfsfgkpjd"
我想得到:
4189 : 3
4210 : 2
4195 : 1
我知道如何在mysql
或通过awk / sort / head ...来做到这一点,但是在elasticsearch
我迷路了。
确切的工作方式取决于您的分析器,但是如果您仅使用默认的标准分析器 ,则可以通过术语聚合轻松获得所需的内容。
作为一个简单的示例,我建立了一个简单的索引:
PUT /test_index
{
"settings": {
"number_of_shards": 1
}
}
然后使用批量api为发布的数据编制索引:
POST /test_index/doc/_bulk
{"index":{"_id":1}}
{"msg":"cgn:4189, dfsdkfldslfs"}
{"index":{"_id":2}}
{"msg":"cgn:4210, aezfvdsvgds"}
{"index":{"_id":3}}
{"msg":"cgn:4189, fdsmpfjdjs"}
{"index":{"_id":4}}
{"msg":"cgn:4195, cvsf"}
{"index":{"_id":5}}
{"msg":"cgn:4189, mkpjd"}
{"index":{"_id":6}}
{"msg":"cgn:4210, mfsfgkpjd"}
然后,我可以运行一个简单的术语聚合,以获取所有术语及其出现的频率(默认情况下,按术语频率降序排列):
POST /test_index/_search?search_type=count
{
"aggs": {
"msg_terms": {
"terms": {
"field": "msg"
}
}
}
}
返回:
{
"took": 4,
"timed_out": false,
"_shards": {
"total": 1,
"successful": 1,
"failed": 0
},
"hits": {
"total": 6,
"max_score": 0,
"hits": []
},
"aggregations": {
"msg_terms": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": "cgn",
"doc_count": 6
},
{
"key": "4189",
"doc_count": 3
},
{
"key": "4210",
"doc_count": 2
},
{
"key": "4195",
"doc_count": 1
},
{
"key": "aezfvdsvgds",
"doc_count": 1
},
{
"key": "cvsf",
"doc_count": 1
},
{
"key": "dfsdkfldslfs",
"doc_count": 1
},
{
"key": "fdsmpfjdjs",
"doc_count": 1
},
{
"key": "mfsfgkpjd",
"doc_count": 1
},
{
"key": "mkpjd",
"doc_count": 1
}
]
}
}
}
这是我使用的代码:
http://sense.qbox.io/gist/a827095b675596c4e3d545ce963cde3fae932156
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