[英]Python. How to sum up all even integers in a list?
我对这个主题完全陌生,我想问一下如何总结列表中的所有偶数(不使用函数(我还没有研究过它们))? 例如:
myList = [1, 3, 5, 6, 8, 10, 34, 2, 0, 3]
我创建 for 循环
for i in myList:
if x % 2 ==0:
# I'm stuck here
如何存储这些值来计算总和?
使用生成器表达式:
>>> myList = [1, 3, 5, 6, 8, 10, 34, 2, 0, 3]
>>> sum(num for num in myList if not num%2)
60
使用filter()
:
>>> myList = [1, 3, 5, 6, 8, 10, 34, 2, 0, 3]
>>> sum(filter(lambda x: not x%2, myList))
60
使用手动循环:
>>> myList = [1, 3, 5, 6, 8, 10, 34, 2, 0, 3]
>>> result = 0
>>> for item in myList:
... if not item%2:
... result += item
...
>>> result
60
对不起,我只是不得不打高尔夫球。 也许它会教某人~ 运算符。
>>> myList = [1, 3, 5, 6, 8, 10, 34, 2, 0, 3]
>>> sum(~i%2*i for i in myList)
60
找到另一个长度相同的:
>>> sum(i&~i%-2for i in myList)
60
您需要将结果存储在变量中并将偶数添加到变量中,如下所示:
>>> myList = [1, 3, 5, 6, 8, 10, 34, 2, 0, 3]
>>> result = 0 # Initialize your results variable.
>>> for i in myList: # Loop through each element of the list.
... if not i % 2: # Test for even numbers.
... result += i
...
>>> print(result)
60
>>>
您可以像这样过滤掉所有非偶数元素
my_list = [1, 3, 5, 6, 8, 10, 34, 2, 0, 3]
even_list = filter(lambda x: x%2 == 0, my_list)
然后像这样总结输出:
sum(even_list)
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