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[英]why does pointer in structure occur error in Visual C++ but GCC doesn't?
[英]Why doesn't buffer overflow occur with GCC?
我刚刚学习缓冲区溢出。 我试图使用GCC复制它。 这是我写的代码。
#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[])
{
int value = 5;
char buffer_one[8], buffer_two[8];
strcpy(buffer_one, "one");
strcpy(buffer_two, "two");
printf("[BEFORE] buffer_two is at %p and contains %s\n", buffer_two, buffer_two);
printf("[BEFORE] buffer_one is at %p and contains %s\n", buffer_one, buffer_one);
printf("[BEFORE] value is at %p and contains %d\n\n", value, value);
printf("[STRCPY] copying %d bytes into buffer_two\n\n", strlen(argv[1]));
strcpy(buffer_two, argv[1]);
printf("[BEFORE] buffer_two is at %p and contains %s\n", buffer_two, buffer_two);
printf("[BEFORE] buffer_one is at %p and contains %s\n", buffer_one, buffer_one);
printf("[BEFORE] value is at %p and contains %d\n\n", value, value);
return 0;
}
好像它应该工作,对吗? Buffer_two和buffer_one在内存中彼此相邻。
[BEFORE] buffer_two is at 0x7fff56ff2b68 and contains two
[BEFORE] buffer_one is at 0x7fff56ff2b70 and contains one
[BEFORE] value is at 0x5 and contains 5
然而,在此之后不久......
[STRCPY] copying 14 bytes into buffer_two
Abort trap: 6
C怎么认识到这个? 一些黑客如何执行实际工作的更复杂的缓冲区溢出?
为什么GCC不会发生缓冲区溢出?
嗯,这种情况正好发生在你的情况下。 这就是为什么,作为副作用,您可以看到中止消息。
发生缓冲区溢出时未完成的情况 。 这意味着任何事情都可能发生。 例如, 恶魔可能会从你的鼻子飞出来 。
这里发生的事情是你的程序崩溃了。 我宁愿无聊的待着。
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