[英]why does pointer in structure occur error in Visual C++ but GCC doesn't?
[英]Why doesn't buffer overflow occur with GCC?
我剛剛學習緩沖區溢出。 我試圖使用GCC復制它。 這是我寫的代碼。
#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[])
{
int value = 5;
char buffer_one[8], buffer_two[8];
strcpy(buffer_one, "one");
strcpy(buffer_two, "two");
printf("[BEFORE] buffer_two is at %p and contains %s\n", buffer_two, buffer_two);
printf("[BEFORE] buffer_one is at %p and contains %s\n", buffer_one, buffer_one);
printf("[BEFORE] value is at %p and contains %d\n\n", value, value);
printf("[STRCPY] copying %d bytes into buffer_two\n\n", strlen(argv[1]));
strcpy(buffer_two, argv[1]);
printf("[BEFORE] buffer_two is at %p and contains %s\n", buffer_two, buffer_two);
printf("[BEFORE] buffer_one is at %p and contains %s\n", buffer_one, buffer_one);
printf("[BEFORE] value is at %p and contains %d\n\n", value, value);
return 0;
}
好像它應該工作,對嗎? Buffer_two和buffer_one在內存中彼此相鄰。
[BEFORE] buffer_two is at 0x7fff56ff2b68 and contains two
[BEFORE] buffer_one is at 0x7fff56ff2b70 and contains one
[BEFORE] value is at 0x5 and contains 5
然而,在此之后不久......
[STRCPY] copying 14 bytes into buffer_two
Abort trap: 6
C怎么認識到這個? 一些黑客如何執行實際工作的更復雜的緩沖區溢出?
為什么GCC不會發生緩沖區溢出?
嗯,這種情況正好發生在你的情況下。 這就是為什么,作為副作用,您可以看到中止消息。
發生緩沖區溢出時未完成的情況 。 這意味着任何事情都可能發生。 例如, 惡魔可能會從你的鼻子飛出來 。
這里發生的事情是你的程序崩潰了。 我寧願無聊的待着。
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