一种更简单的方式来引用所需字典（Python）的索引？

Question

问题感觉它的措辞很差，如果你同意的话可以随意调整它，并且知道如何更好地表达它。

我有以下代码：

def owned_calendars(cal_items):
    """Returns only the calendars in which the user is marked as "owner"

    """
    owner_cals = []
    for entry in cal_items:
        if entry['accessRole'] == "owner":
            owner_cals.append(cal_items[cal_items.index(entry)])

    return owner_cals

cal_items是一个dictionaries list

在我编写owner_cals.append(cal_items[cal_items.index(entry)])我正在尝试附加具有属性accessRole = owner的字典。

这条线似乎超长而且笨重，我想知道是否有更容易/更直观的方法来做到这一点？

Answer 1

尝试这个。 您可以使用列表推导在一行中执行此操作。

owner_cals = [x for x in cal_items if x["access_role"]=="owner"]

您还可以使用enumerate方法。

owner_cals = [j for i,j in enumerate(cal_items) if j["access_role"]=="owner"]

另外，请记住.index()返回找到item的最低索引 。

["foo", "bar", "baz", "bar"].index("bar")将始终返回1。