如何使我的if语句输出正确的printf C程序

Question

在下面的代码中，我制作了一个程序，可以将您转账的金额转化为单词。 例如，“ 1234.56”变成“一千二百三十四和... 56美分”。 问题是，当我尝试在scanf输入金额“ 0.01”时，输出应为“ Zero Dollars and ... 1 Cent”，输出为“ Dollars and ... 1 Cents”。 请帮忙！

代码如下：

#include <stdio.h>

void printNum(int);
void printNum2(int);

int main()
{

    int a = 0;
    int b = 0;
    int c = 0;
    int d = 0; 
    int num = 0;
    int printcents; //To convert the float "cents" to an integer.

    float inclusive;
    float cents;

    printf("Welcome to the IPC144 Cheque Generator!!\n");
    printf("PAY TO THE ORDER OF... amahmood29 (018359133)\n");
    printf("Enter a monetary value from $0.01 to $9999.99 inclusive: ");
    scanf("%f", &inclusive);

    if(inclusive < 0.00 || inclusive >= 10000.00) {
        printf("Sorry, cannot create cheque for that amount, try again next time!\n");
    }
    else
    {                                             
        a = inclusive / 1000;                          //This data is replacing our variable by diving whatever the vaulue is by either 1000, 100, 10.
        inclusive = inclusive - (a*1000);
        b = inclusive / 100; 
        inclusive = inclusive - (b*100);
        if ( inclusive > 19 ){
            c = inclusive / 10; 
            inclusive = inclusive - (c*10);
        }
        else
        {
            c = inclusive;
            d = 0;
        }
        d = inclusive;
        num = inclusive;
        cents = (inclusive - num)*100; //To calculate our "Cents" with numerals.
        printcents = cents;


        /*Printing if the variables are in the thousands, hundreds, tens or ones categories.*/
        if (a > 0){ 
            printNum(a);  
            printf("Thousand ");
        }
        if (b > 0){
            printNum(b);
            printf("Hundred ");
        }
        printNum2(c);   
        if (d >= 0){
            printNum(d);
            printf("Dollars and ... ");
        }
        else if (c == 0 && b == 0 && a == 0){
            printf("Zero Dollars and ... ");
        }
        printf("%d", printcents);
        printf(" Cents\n");
    }
}

void printNum(int x)  //Created functions to easily output various if statements.
{

    if ( x == 1)
        printf("One ");
    else if ( x == 2)
        printf("Two ");
    else if (x == 3)
        printf("Three ");
    else if (x == 4) 
        printf("Four ");
    else if (x == 5)
        printf("Five ");
    else if (x == 6)
        printf("Six ");
    else if (x == 7)
        printf("Seven ");
    else if (x == 8)
        printf("Eight ");
    else if (x == 9)
        printf("Nine ");

    }

void printNum2(int x)
{
    if ( x == 10)
        printf("Ten ");
    else if ( x == 11)
        printf("Eleven ");
    else  if ( x == 12)
        printf("Twelve ");
    else if ( x == 13)
        printf("Thirteen ");
    else if (x == 14)
        printf("Fourteen ");
    else if (x == 15)
        printf("Fifteen ");
    else if (x == 16)
        printf("Sixteen ");
    else if (x == 17)
        printf("Seventeen ");
    else if (x == 18)
        printf("Eighteen ");
    else if (x == 19)
        printf("Nineteen ");
    else if (x == 2)
        printf("Twenty ");
    else if (x == 3)
        printf("Thirty ");
    else if (x == 4)
        printf("Forty ");
    else if (x == 5)
        printf("Fifty ");
    else if (x == 6)
        printf("Sixty ");
    else if (x == 7)
        printf("Seventy ");
    else if (x == 8)
        printf("Eighty ");
    else if (x == 9)
        printf("Ninety ");
}

Answer 1

if else可以使用嵌套。 首先检查是否为零美元，否则执行您的过程。 尝试这样的事情：

if (c == 0 && b == 0 && a == 0){
   printf("Zero Dollars and ... ");
}
else{
   if (a > 0){
      printNum(a);
      printf("Thousand ");
   }
   if (b > 0){
      printNum(b);
      printf("Hundred ");
   }
   printNum2(c);
   if (d >= 0){
      printNum(d);
      printf("Dollars and ... ");
   }
}

代替

if (a > 0){ 
   printNum(a);  
   printf("Thousand ");
}
if (b > 0){
   printNum(b);
   printf("Hundred ");
}
printNum2(c);   
if (d >= 0){
   printNum(d);
   printf("Dollars and ... ");
}
else if (c == 0 && b == 0 && a == 0){
   printf("Zero Dollars and ... ");

就像您的代码中的if(d>=0) ，它将永远不会输入else if语句（ else if前面的任何语句为true， else if跳过）。

Answer 2

快速浏览，但：

if (d > 0){
    .....

再次，这是一个快速的外观，我没有测试。