如何将函数内部的printf输出输出到c中的主程序

Question

我有一个功能，可以打印很多printf语句，输出的行数不是固定的。 我需要将所有在myFun打印的myFun移至主要功能，并将其用于其他目的。 有人可以指导如何做吗？

#include<stdio.h>


int myFun(char* name){
    printf("myFun: this is important line too\n");
    printf("myFun: my name is %s\n",name);
    printf("myFun: this is a important line needed in main, genrated from some function called inside myFun\n");
}

int main(){


    printf("this is main and now calling myFun\n");
    myFun("monk");

    //how can I get all the output of all three printf statements done inside myFun to the main function ?


    return 0;
}

Answer 1

您可以尝试将字符串保存到数组中，然后return整个数组：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char **Func(char *name)
{
    int numOfOutputs = 3;
    numOfOutputs++; //Append an extra null byte to the end so we know when it ends
    int maximumStringSize = 100;
    char **final = (char **)malloc(numOfOutputs * sizeof(char *));
    for (int i = 0; i < numOfOutputs; i++)
        final[i] = (char *)malloc(maximumStringSize * sizeof(char));

    strcpy(final[0], "myFun: this is important line too\n");
    sprintf(final[1], "myFun: my name is %s\n", name);
    strcpy(final[2], "myFun: this is a important line needed in main, genrated from some function called inside myFun\n");

    //Final member assigned as NULL to indicate end
    final[3] = NULL;
    return final;
}
int main()
{
    printf("this is main and now calling myFun\n");
    char **result = Func("monk");
    //Print result, check for ending member with the nullbyte we added
    for(int i = 0 ; result[i] != NULL; i++)
        printf("For i = %d, string is -> %s", i, result[i]);
    //Don't forget to free with something like this:
    for(int i = 0 ; result[i] != NULL; i++)
        free(result[i]);
    free(result);
    return 0;
}