[英]Deserialize XML - how do I deserialize nested lists?
我试图反序列化此XML:
<Response>
<Make Name="Audi">
<Model Name="A7">
<Specs>
<Spec Identifier="330025">...</Spec>
<Spec Identifier="330026">...</Spec>
<Spec Identifier="330027">...</Spec>
<Spec Identifier="330028">...</Spec>
<Spec Identifier="330008">...</Spec>
<Spec Identifier="330038">...</Spec>
<Spec Identifier="330024">...</Spec>
<Spec Identifier="330019">...</Spec>
<Spec Identifier="330020">...</Spec>
我只对“规格”列表感兴趣,但似乎无法反序列化它。 我尝试了以下方法:
类:
[XmlRoot]
public class Response
{
[XmlArray("Specs"), XmlArrayItem("Spec")]
public List<Spec> Results { get; set; }
//[XmlArray("Specs"), XmlArrayItem("Spec")]
public List<Make> Make { get; set; }
}
public class Spec
{
[XmlAttribute("YearProductionStarts")]
public string YearProductionStarts { get; set; }
[XmlAttribute("YearProductionEnd")]
public string YearProductionEnd { get; set; }
}
public class Make
{
public List<Model> Model { get; set; }
}
public class Model
{
public List<Spec> Spec { get; set; }
}
并使用此方法进行反序列化而没有任何乐趣:
//Deserialize responseXml to response object
var xmLserializer = new XmlSerializer(typeof(ResponseGetSpec));
using (var reader = new StringReader(responseXml))
{
return (ResponseGetSpec)xmLserializer.Deserialize(reader);
}
您可以在Model
以及Response
内使用规格。 XML的设置方式将进入Model
。
您还需要所有其他项目的属性。
从这样的东西开始
[XmlRoot]
public class Response
{
[XmlElement("Make")] // Use XmlElement to get multiple items without a containing XML tag
public List<Make> Make { get; set; }
}
public class Spec
{
[XmlAttribute("YearProductionStarts")]
public string YearProductionStarts { get; set; }
[XmlAttribute("YearProductionEnd")]
public string YearProductionEnd { get; set; }
}
public class Make
{
[XmlElement("Model")]
public List<Model> Model { get; set; }
}
public class Model
{
[XmlArray("Specs"), XmlArrayItem("Spec")]
public List<Spec> Spec { get; set; }
}
如果那行不通,请创建一个对象并将其序列化,然后查看该XML与您要使用的XML之间的区别。
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