骰子游戏号码不是随机的

Question

基本上我应该模拟一个掷三个骰子的程序，加起来。 然后，我将让用户猜测下一卷是更高，更低，相同还是只是想退出。 我有两个问题。

1. 这些数字不是随机的，显然这对我来说是个很大的错误，但我似乎无法弄清楚。 我想我不需要第二个包含3个骰子对吗？ 他们仍然没有帮助。

2. 无论如何，我的程序一次完成所有if / else if语句。 显然我不希望这种情况发生。

---

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main ()
{
    int diceOne, diceTwo, diceThree, diceSum=0, timesCorrect=0, choice; 
    int newDiceOne, newDiceTwo, newDiceThree, newDiceSum;

    srand( time(NULL) );

    diceOne      = rand() % 6 + 1;
    diceTwo      = rand() % 6 + 1;
    diceThree    = rand() % 6 + 1;
    newDiceOne   = rand() % 6 + 1;
    newDiceTwo   = rand() % 6 + 1;
    newDiceThree = rand() % 6 + 1;

    printf("The three dice rolls: %d, %d, %d", diceOne, diceTwo, diceThree);
    diceSum = diceOne + diceTwo + diceThree;
    printf("\nTotal sum of dice is %d\n", diceSum);

    do {
        printf("Guess higher(1), lower(2), same(3) or quit?(4)\n");
        printf(" You have been correct %d times\n", timesCorrect);
        scanf("%d", &choice);

        printf("The three dice rolls: %d, %d, %d", newDiceOne, newDiceTwo, newDiceThree);
        newDiceSum= newDiceOne + newDiceTwo + newDiceThree;
        printf("\nTotal sum of dice is %d\n", newDiceSum);

        if (choice == 1)
        {
            if (newDiceSum > diceSum);
                timesCorrect++;
            printf("You are correct!\n");
        }
        else if (newDiceSum < diceSum); 
        {
            printf("You are incorrect, sorry!\n");
        }

        if (choice == 2)
        {
            if (newDiceSum < diceSum);
                timesCorrect++;
            printf("You are correct!\n");
        }
        else if (newDiceSum > diceSum); 
        {
            printf("You are incorrect, sorry!\n");
        }

        if (choice == 3)
        {
            if (newDiceSum == diceSum);
                timesCorrect ++;
            printf("You are correct!\n");
        }
        else if (newDiceSum != diceSum); 
        {
            printf("You are incorrect, sorry!\n");
        }

        if (choice == 4)
        {
            printf("Thanks for playing!!!!!!\n");
            system("pause");

            return 0;
        }
    } while (choice!= 4 );
}

Answer 1

else if有条件，您会在else if后面加上一个多余的分号，例如这里

else if (newDiceSum < diceSum); 
                /*            ^ this should not be here */

如果您使用具有良好诊断能力的编译器并启用警告，则应该警告您“ 错字 ”，如果您想将该块留空，请使用大括号，例如

else if (newDiceSum < diceSum) {}

另外，您可以使用rand()设置第一个骰子，它们是随机值，但是在循环中始终使用相同的值。

Answer 2

如下代码：

1. 处理错误条件

2. 消除不必要的变量

3. 干净地编译

4. 执行成功

---

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main ( void )
{
    int diceOne;
    int diceTwo;
    int diceThree;
    int diceSum=0;
    int timesCorrect=0;
    int choice;

    int newDiceSum;

    srand( time(NULL) );

    diceOne      = rand() % 6 + 1;
    diceTwo      = rand() % 6 + 1;
    diceThree    = rand() % 6 + 1;


    printf("The three dice rolls: %d, %d, %d", diceOne, diceTwo, diceThree);
    diceSum = diceOne + diceTwo + diceThree;
    printf("\nTotal sum of dice is %d\n", diceSum);

    do {
        printf("Guess higher(1), lower(2), same(3) or quit?(4)\n");
        printf(" You have been correct %d times\n", timesCorrect);
        if( 1 != scanf("%d", &choice) )
        { // then scanf failed
            perror( "scanf for choice failed" );
            exit( EXIT_FAILURE );
        }

        // implied else, scanf successful

        diceOne      = rand() % 6 + 1;
        diceTwo      = rand() % 6 + 1;
        diceThree    = rand() % 6 + 1;

        printf("The three dice rolls: %d, %d, %d", diceOne, diceTwo, diceThree);
        newDiceSum = diceOne + diceTwo + diceThree;
        printf("\nTotal sum of dice is %d\n", newDiceSum);

        switch( choice )
        {
        case 1:
            if (newDiceSum > diceSum)
            {
                timesCorrect++;
                printf("You are correct!\n");
            }
            else
            {
                printf("You are incorrect, sorry!\n");
            }
            break;

        case 2:
            if (newDiceSum < diceSum)
            {
                timesCorrect++;
                printf("You are correct!\n");
            }
            else
            {
                printf("You are incorrect, sorry!\n");
            }
            break;

        case 3:
            if (newDiceSum == diceSum)
            {
                timesCorrect ++;
                printf("You are correct!\n");
            }
            else
            {
                printf("You are incorrect, sorry!\n");
            }
            break;

        case 4:
            printf("Thanks for playing!!!!!!\n");
            system("pause");
            break;

        default:
            printf( " invalid choice, valid choices are 1...4\n");
            break;
        } // end switch
    } while (choice!= 4 );
    return(0);
} // end function: main