正则表达式匹配多个定界符

Question

我正在尝试分割以下定界符：句号，分号，*，+ 、? 和-但是，我只想在句子开头出现时对“-”进行拆分（以免拆分“非功能性”之类的词

我尝试了以下操作，但没有任何进展，我们将不胜感激：

sentences = re.split("[.-;]*[\+]*[\?]*[\*]*", txt)

这是我一直在尝试的示例文本：

- Text Editor: Now you can edit plain text files with airport tools
* Updated Dropbox support 
* Improved
stability
- New icon                                                                          
* See this case mis-alignment

拆分后的预期输出是项目列表：

TextEditor: Now you can edit plain text files with airport tools, Updated Dropbox support, Improved stability, New icon, See this case mis-alignment

Answer 1

尝试像这样枚举定界符：

re.split（“ [。; * +？]”）

Answer 2

如果您想将字符串拆分为一组定义的定界符，而不是这样做：

>>> txt = '- Text Editor: Now you can edit plain text files with airport tools'
>>> r = re.split(r'([.;*+?-]+)',txt)
>>> r
['', '-', ' Text Editor: Now you can edit plain text files with airport tools']

如果您不想进入结果列表，请使用以下分隔符：

>>> r = re.split(r'[.;*+?-]+',txt)
>>> r
['', ' Text Editor: Now you can edit plain text files with airport tools']

编辑：为响应您的以下评论，请使用\\s表示空格：

    >>> txt = '''- Text Editor: Now you can edit plain text files with airport tools
    * Updated Dropbox support 
    * Improved
    stability
    - New icon'''
     >>> r = re.split('(^|\s)+[.;*+?-]+($|\s)+',txt) 
     >>> [i for i in r if len(i) > 1]
['Text Editor: Now you can edit plain text files with airport tools', 'Updated Dropbox support', 'Improved\n    stability', 'New icon']

Answer 3

您可以使用此re.split函数。

>>> import re
>>> s = '''- Text Editor: Now you can edit plain text files with airport tools
* Updated Dropbox support 
* Improved
stability
- New icon'''
>>> [i for i in re.split(r'(?m)\s*^[-*+?]+\s*', s) if i]
['Text Editor: Now you can edit plain text files with airport tools', 'Updated Dropbox support', 'Improved\nstability', 'New icon']