[英]Swift parse json to struct
我有一个像
struct Channel {
var id : Int = 0
var name = ""
}
我从URL获取json作为
{"channel_list":[{"channel_id":0,"channel_name":"test1"},{"channel_id":0,"channel_name":"test2"}]}
但是我无法获取数据
func parseJson(anyObj:AnyObject) -> Array<Channel>{
var list:Array<Channel> = []
if anyObj is Array<AnyObject> {
var b:Channel = Channel()
for json in anyObj as! Array<AnyObject>{
b.id = (json["channel_id"] as AnyObject? as? Int) ?? 0
b.name = (json["channel_name"] as AnyObject? as? String) ?? ""
list.append(b)
}
}
return list
}
//read code
let anyObj: AnyObject? = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions(0),error: nil) as AnyObject?
println(anyObj)
if let myobj=anyObj["channel_list"] as AnyObject {
self.Channellist=self.parseJson(anyObj!)
}
这怎么了
首先,不要使用AnyObject
,而应将JSON响应转换为字典: [NSObject:AnyObject]
然后将anyObj["channel_list"]
的结果安全地anyObj["channel_list"]
为字典数组[[NSObject:AnyObject]]
,因为这是您的JSON响应格式。
然后,您需要在parseJSON
函数中使用此类型。 我们还在简化它,因为不再需要进行怪异的转换。
另外,您将错误的参数传递给函数(使用anyObj
而不是myObj
)。
struct Channel {
var id : Int = 0
var name = ""
}
func parseJson(anyObj: [[NSObject:AnyObject]]) -> Array<Channel>{
var list: Array<Channel> = []
var b: Channel = Channel()
for json in anyObj {
b.id = (json["channel_id"] as? Int) ?? 0
b.name = (json["channel_name"] as? String) ?? ""
list.append(b)
}
return list
}
if let anyObj = NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions(0),error: nil) as? [NSObject:AnyObject] {
if let myobj = anyObj["channel_list"] as? [[NSObject:AnyObject]] {
self.Channellist=self.parseJson(myobj)
}
}
仍有改进的空间:例如,您可以为Struct创建一个初始化程序,还可以为响应类型创建类型别名,使用map
创建列表,等等。
这就是我使用Swift 2的方法:
struct Channel {
var id : Int
var name: String
init?(JSON: [NSObject: AnyObject]?) {
guard let channelID = json["channel_id"] as? Int, let channelName = json["channel_name"] as? String
else { name = ""; id = 0; return nil }
name = channelName
id = channelID
}
}
func parseJSON(array: [[NSObject:AnyObject]]) -> [Channel?] {
return array.map { Channel(JSON: $0) }
// If you don't want to return optionals to channel you can do this instead:
// return array.map { Channel(JSON: $0) }.filter { $0 != nil }.map { $0! }
}
// And in the caller
do {
guard let dict = try NSJSONSerialization.JSONObjectWithData(data!, options: []) as? [NSObject : AnyObject]
else { throw NSError(domain ... // Setup error saying JSON wasn't parsed. }
guard let arrayContents = dict["channel_list"] as? [[NSObject:AnyObject]]
else { throw NSError(domain ... // Setup error saying array wasn't found. }
let channels = parseJSON(arrayContents)
}
catch {
print(error)
}
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