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[英]MySQL with Python Flask in Openshift: Internal Server Error
[英]internal server error Flask - Python
这是我在Python-Flask中的代码。 在这里,我要输入剧院(剧院表)的数据,然后获取相应的ID,然后将屏幕添加到“屏幕”表中的相应theatre_id。
问题是Theatre被添加到数据库中,并且我能够获取ID。 Screen的代码似乎不起作用(如果我注释掉session.screen add和commit语句,for循环也可以工作)并且如果没有发生屏幕提交,即使回滚也不会发生。
session_theatre = Session_theatre()
session_screen = Session_screen()
id = 1
if request.method == "POST":
if form.validate_on_submit():
name = str(form.name.data)
city = str(form.location.data)
address = str(form.address.data)
no_of_screen = int(form.total_no_screen.data)
if (name !="" and name!=" " and city != "" and city != " " and address != ""and address != " " and no_of_screen != None):
t = Theatre(name,city,address,1)
try:
session_theatre.add(t)
session_theatre.commit()
query = session_theatre.query(Theatre).filter_by(name=name,city =city).all()
for i in query :
id = i
for i in range (0,no_of_screen):
flash(id)
screen = Screen(str(i+1),1,20,1,20,id)
session_screen.add(screen)
session_screen.commit()
flash("Successfully added !!")
except :
session_screen.rollback()
session_theatre.rollback()
flash("Oops something went wrong !!")
finally:
session_screen.close()
session_theatre.close()
else :
flash("Please fill the input")
return render_template('admin/add_theatre.html',form = form)
屏幕型号
class Screen(db.Model):
__tablename__ = "screens"
id = db.Column(db.Integer,primary_key=True)
screen_num = db.Column(db.String(1))
seat_row_start = db.Column(db.Integer)
seat_row_end = db.Column(db.Integer)
seat_col_start = db.Column(db.Integer)
seat_col_end = db.Column(db.Integer)
theatre_id = db.Column(db.Integer, db.ForeignKey('theatres.id'))
def __init__(self, screen_num,
seat_row_start,seat_row_end,seat_col_start,seat_col_end,theatre_id):
self.screen_num = screen_num
self.seat_row_start = seat_row_start
self.seat_row_end = seat_row_end
self.seat_col_start = seat_col_start
self.seat_col_end = seat_col_end
self.theatre_id = theatre_id
要从session_theatre
的查询中获取列表,必须在末尾添加all()
:
query = session_theatre.query(Theatre).filter_by(name=name,city =city).all()
该查询返回Theatre
对象列表,您可以访问遍历列表的每个Theatre
对象的id
属性,并通过其名称访问该属性:
for obj in query :
for i in range (0,no_of_screen):
flash(obj.id)
screen = Screen(i+1,1,20,1,20,obj.id)
session_screen.add(screen)
session_screen.commit()
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