[英]How can I run executable in assets?
如何将可执行文件添加到资源中并在Android中运行并显示输出?
我有一个可行的可执行文件。 我假设代码中需要一些chmod
。
谢谢。
将您的可执行文件放在原始文件夹中,然后像在这里一样使用ProcessBuilder或Runtime.exec运行它http://gimite.net/en/index.php?Run%20native%20executable%20in%20Android%20App
这是我的答案
将copyAssets()放到mainactivity中。
某人的代码:
private void copyAssets() {
AssetManager assetManager = getAssets();
String[] files = null;
try {
files = assetManager.list("");
} catch (IOException e) {
Log.e("tag", "Failed to get asset file list.", e);
}
for(String filename : files) {
InputStream in = null;
OutputStream out = null;
try {
in = assetManager.open(filename);
File outFile = new File(getFilesDir(), filename);
out = new FileOutputStream(outFile);
copyFile(in, out);
} catch(IOException e) {
Log.e("tag", "Failed to copy asset file: " + filename, e);
}
finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
// NOOP
}
}
if (out != null) {
try {
out.close();
} catch (IOException e) {
// NOOP
}
}
}
}
}
private void copyFile(InputStream in, OutputStream out) throws IOException {
byte[] buffer = new byte[1024];
int read;
while ((read = in.read(buffer)) != -1) {
out.write(buffer, 0, read);
}
}
这里还有运行命令的代码
public String runcmd(String cmd){
try {
Process p = Runtime.getRuntime().exec(cmd);
BufferedReader in = new BufferedReader(new InputStreamReader(p.getInputStream()));
int read;
char[] buffer = new char[4096];
StringBuffer out = new StringBuffer();
while ((read = in.read(buffer)) > 0) {
out.append(buffer, 0, read);
}
in.close();
p.waitFor();
return out.substring(0);
} catch (IOException e) {
throw new RuntimeException(e);
} catch (InterruptedException e) {
throw new RuntimeException(e);
}
}
您可能需要将其更改为
String prog= "programname";
String[] env= { "parameter 1","p2"};
File dir= new File(getFilesDir().getAbsolutePath());
Process p = Runtime.getRuntime().exec(prog,env,dir);
确保正确的参数处理
还要将其添加到主代码中以检查文件的正确复制
String s;
File file4 = new File(getFilesDir().getAbsolutePath()+"/executable");
file4.setExecutable(true);
s+=file4.getName();
s+=file4.exists();
s+=file4.canExecute();
s+=file4.length();
//output s however you want it
应该写:filename,true,true,正确的文件长度。
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