[英]getting at namespace data when Parsing Xml on Python 2.6.6 with ElementTree 1.2.6
我有一些需要解析的xml,以以下格式提供:
<Pres xmlns:abset="titan:arm:params:xml:ns:keyprov:abset">
<Set>
<Key>
<Id>c91e3882-e6f3-41f9-af52-3473a2c4615a</Id>
<abset:Data>
<abset:Tag>
<abset:Value>i need this</abset:Value>
</abset:Tag>
</abset:Data>
</Key>
</Set>
</Pres>
使用Python 2.7,我可以使用以下内容获得abset:Value:
xmlstr = '...'
root = ElementTree.fromstring(xmlstr)
ns = {'abset' : 'titan:arm:params:xml:ns:abset'}
keyElement = root.find("./Set/Key")
value = keyElement.find("./abset:Data/abset:Tag/abset:Value", ns).text
但是在python 2.6中,find命令不支持ns参数。
我已经尝试过ValElement = root.find(“ ./ Set / Key / abset:Data / abset:Tag / abset:Value”)value = ValElement.text
但是我得到的错误是
keyelement = root.find("./Set/Key/abset:Data/abset:Tag/abset:Value")
File "/usr/lib64/python2.6/xml/etree/ElementTree.py", line 330, in find
return ElementPath.find(self, path)
File "/usr/lib64/python2.6/xml/etree/ElementPath.py", line 186, in find
return _compile(path).find(element)
File "/usr/lib64/python2.6/xml/etree/ElementPath.py", line 176, in _compile
p = Path(path)
File "/usr/lib64/python2.6/xml/etree/ElementPath.py", line 93, in __init__
"expected path separator (%s)" % (op or tag)
SyntaxError: expected path separator (:)
如何在python 2.6.6中访问这些元素?
您将需要完整指定名称空间,因此应该使用root.find("./Set/Key/{titan:arm:params:xml:ns}Data/{titan:arm:params:xml:ns}Tag/{titan:arm:params:xml:ns}Value")
来代替root.find("./Set/Key/abset:Data/abset:Tag/abset:Value")
root.find("./Set/Key/{titan:arm:params:xml:ns}Data/{titan:arm:params:xml:ns}Tag/{titan:arm:params:xml:ns}Value")
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