[英]Nested loops in dictionary comprehension
我有一个现有的字典列表如下:
FA = [{u'child': [{u'cdesc': u'Audit'},
{u'cdesc': u'Equity Research'},
{u'cdesc': u'Finance / Accounts / Tax'},
{u'cdesc': u'Investment Banking / M&A'}],
u'pdesc': u'Finance / Accounts / Investment Banking',
u'pid': 10007}]
我想将它转换为这样的东西:
FA = {u'Audit':2,
u'Equity Research':2,
u'Finance / Accounts / Tax':2,
u'Investment Banking / M&A':2,
u'Finance / Accounts / Investment Banking':2}
我可以使用嵌套循环轻松完成此操作,其代码如下所示。 有没有办法使用词典理解来做到这一点?
a = dict()
for fa in FA:
a.update({slugify(fa['pdesc']):2})
for c in fa['child']:
a.update({slugify(c['cdesc']):2})
字典理解在这里看起来很丑陋...无论如何......
# METHOD 1
FA_dict1 = {d:2 for v in FA[0][u'child'] for d in v.values()}
FA_dict1.update({FA[0][u'pdesc']: 2})
# METHOD 2
from itertools import chain
FA_dict = {d:2 for v in FA[0][u'child'] for d in chain(v.values(), [FA[0][u'pdesc']])}
# METHOD 3
FA_DICT = {d:2 for v in FA[0][u'child'] for d in list(v.values())+[FA[0][u'pdesc']]}
理解解决方案确实是一只丑小鸭!
在上面的数据上运行:
{ k:2 for k in reduce(lambda x,y: x+y, [ [ chld[u'cdesc'] for chld in FA[0]['child'] ], [ FA[0][u'pdesc'] ] ] ) }
{u'Audit': 2,
u'Equity Research': 2,
u'Finance / Accounts / Investment Banking': 2,
u'Finance / Accounts / Tax': 2,
u'Investment Banking / M&A': 2}
这会让你开始吗?
{ chld[u'cdesc']:2 for chld in FA[0]['child'] }
哪个产生(不是100%但是接近):
{u'Audit': 2,
u'Equity Research': 2,
u'Finance / Accounts / Tax': 2,
u'Investment Banking / M&A': 2}
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