使用Python在列表中查找偶数个数

Question

我正在寻找最有效的方法来检查列表中的一个或多个元素是否是具有预定义公差的预定义数字的倍数。 下面是一个示例：

myNumber=3.5
myList=[0,0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5,7,7.5,8,8.5,9,9.5]
myTolerance=0.5

myResult=[0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,0,0,0,0]

任何建议都非常感谢。

Answer 1

怎么样

from numpy import mod, floor
withinTolAbove=[int(mod(number, myNumber) <= myTolerance and
                mod(floor(number / myNumber), 2) == 0) for number in myList]
withinTolBelow=[int(mod(number + myTolerance, myNumber) <= myTolerance and
                mod(floor((number + myTolerance) / myNumber), 2) == 0) for number in myList]
myResult=[max(i1, i2) * int(number > myTolerance) for i1, i2, number in zip(withinTolAbove, withinTolBelow, myList)]

第一部分确定除法是否在整数的公差范围内，第二部分确定该整数是否可被2整除。

Answer 2

怎么样

print print([int(abs(x - round(x / myNumber) * myNumber) <= myTolerance and round(x / myNumber) > 1.5) for x in myList])

输出：

[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0]