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使用Elasticbeanstalk部署Flask时出现AWS mod_wsgi错误

[英]AWS mod_wsgi error when deploying Flask with elasticbeanstalk

在Elasticbeanstalk上使用flask获得以下错误:

/opt/python/run/venv/bin/python3: can't open file 'mod_wsgi': [Errno 2] No such file or directory
[Sat Aug 08 23:43:35.994357 2015] [:error] [pid 7748] [remote 127.0.0.1:45363] mod_wsgi (pid=7748): Target WSGI script '/opt/python/current/app/application.py' cannot be loaded as Python module.
[Sat Aug 08 23:43:35.994407 2015] [:error] [pid 7748] [remote 127.0.0.1:45363] mod_wsgi (pid=7748): SystemExit exception raised by WSGI script '/opt/python/current/app/application.py' ignored.
[Sat Aug 08 23:43:35.994449 2015] [:error] [pid 7748] [remote 127.0.0.1:45363] Traceback (most recent call last):
[Sat Aug 08 23:43:35.994511 2015] [:error] [pid 7748] [remote 127.0.0.1:45363]   File "/opt/python/current/app/application.py", line 3, in <module>
[Sat Aug 08 23:43:35.994518 2015] [:error] [pid 7748] [remote 127.0.0.1:45363]     app.run(debug=True)
[Sat Aug 08 23:43:35.994553 2015] [:error] [pid 7748] [remote 127.0.0.1:45363]   File "/opt/python/run/venv/lib/python3.4/site-packages/flask/app.py", line 772, in run
[Sat Aug 08 23:43:35.994560 2015] [:error] [pid 7748] [remote 127.0.0.1:45363]     run_simple(host, port, self, **options)
[Sat Aug 08 23:43:35.994590 2015] [:error] [pid 7748] [remote 127.0.0.1:45363]   File "/opt/python/run/venv/lib/python3.4/site-packages/werkzeug/serving.py", line 623, in run_simple
[Sat Aug 08 23:43:35.994596 2015] [:error] [pid 7748] [remote 127.0.0.1:45363]     reloader_type)
[Sat Aug 08 23:43:35.994624 2015] [:error] [pid 7748] [remote 127.0.0.1:45363]   File "/opt/python/run/venv/lib/python3.4/site-packages/werkzeug/_reloader.py", line 231, in run_with_reloader
[Sat Aug 08 23:43:35.994630 2015] [:error] [pid 7748] [remote 127.0.0.1:45363]     sys.exit(reloader.restart_with_reloader())
[Sat Aug 08 23:43:35.994652 2015] [:error] [pid 7748] [remote 127.0.0.1:45363] SystemExit: 2

我正在使用elasticbeanstalk命令行界面来部署flask应用程序。

您正在生产中使用app.run 不要在生产中使用开发服务器。

像任何WSGI应用程序服务器一样, mod_wsgi希望在导入时找到一个application实例,但是您正在运行开发服务器。

防止在导入时运行开发服务器。 根据您的mod_wsgi设置,可能期望名称为application而不是app

application = app

if __name__ == '__main__':
    app.run()

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