在CTRL + C之后如何关闭在线程中运行的Python套接字？

Question

我在python中有一个多线程程序，我想在CTRL + C（或Z）后关闭套接字。 我试过这个和这个 ，但他们没有工作过。

尝试重新运行程序时，出现错误消息：

绑定失败。 错误代码：98消息地址已在使用中，称为Traceback（最近一次调用）：文件“ main.py”，位于main.connection.close（）中的第16行，名称错误：未定义名称“ main”

from connection import Connection
class Main():
    def __init__(self):
        self.connection = Connection()                       
        self.connection.start()                      
if __name__ == '__main__':
    try:
        main = Main()
    except:
        main.connection.close()


import socket
import sys
import threading
import time
class Connection(threading.Thread):  
    def __init__(self, group=None, target=None, name=None, args=(), kwargs=None, verbose=None):
        threading.Thread.__init__(self, group=group, target=target, name=name, args=args, kwargs=kwargs, verbose=verbose) 

        self.server = None
        self.connection = self.start_connention()
        self.data = "null"    
        self.lock = threading.Lock()  
        self.OK = True        

    def start_connention(self):
        host = '192.168.42.1'
        port = 8888

        s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
        s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) 
        print 'Socket created'

        #Bind socket to local host and port
        try:
            s.bind((host, port))
        except socket.error, msg:
            print 'Bind failed. Error code: ' + str(msg[0]) + ' Message ' + msg[1]
            sys.exit()  

        print 'Socket bind complete'

        #Start listening on socket
        s.listen(10)
        print 'Socket now listening on ' + str(port)

        connection, addr = s.accept()
        print 'Connected with ' + addr[0] + ':' + str(addr[1])                

        self.server = s

        return connection

    def close(self):
        print("closing")
        self.OK = False
        self.server.close()

    def run(self):
        while self.OK:            
            with self.lock:
                self.data = self.connection.recv(4096)
                print(str(self.data))
            time.sleep(0.02)


    def send(self, message):
        self.connection.sendall(message)

Answer 1

从文档：KeyboardInterrupt继承自BaseException，以免被捕获Exception的代码意外捕获，从而防止解释器退出。 docs

if __name__ == '__main__':  
    try:
       main = Main()
    except KeyboardInterrupt:
        pass
    finally:
        main.connection.close()

Answer 2

我建议您对这些东西使用atexit模块。 只需将此行放在__init__中，以防任何python进程终止，连接将关闭

atexit.register(self.close)