在python中打印子节点及其xml标记

Question

我有一个名为m.xml的文件，其内容如下：

<volume name="sp" type="span" operation="create">
    <driver>HDD1</driver>
    <driver>HDD2</driver>
    <driver>HDD3</driver>
    <driver>HDD4</driver>
</volume>

我想得到如下结果：

<driver>HDD1</driver>
<driver>HDD2</driver>
<driver>HDD3</driver>
<driver>HDD4</driver>

我正在尝试使用以下代码

import xml.etree.ElementTree as ET
root = ET.parse('m.xml')
for nod in root.findall("./driver"):
    print nod.text

我得到以下结果：

HDD1
HDD2
HDD3
HDD4

如何获得标签，而不仅仅是文本值？

Answer 1

要将元素显示为XML文本，请使用ElementTree.tostring()函数 ：

import xml.etree.ElementTree as ET
root = ET.parse('m.xml')
for nod in root.findall("./driver"):
    print ET.tostring(nod)

演示：

>>> import xml.etree.ElementTree as ET
>>> root = ET.fromstring('''\
... <volume name="sp" type="span" operation="create">
...     <driver>HDD1</driver>
...     <driver>HDD2</driver>
...     <driver>HDD3</driver>
...     <driver>HDD4</driver>
... </volume>
... ''')
>>> for nod in root.findall("./driver"):
...     print ET.tostring(nod)
... 
<driver>HDD1</driver>

<driver>HDD2</driver>

<driver>HDD3</driver>

<driver>HDD4</driver>

Answer 2

使用BeautifulSoup解析XML。 很简单：

from bs4 import BeautifulSoup as Soup

with open("sample.xml", "r") as f:
    target_xml = f.read()

# create a `Soup` object
soup = Soup(target_xml, "xml")                                                                                                        

# loop through all <driver> returned as a list and prints all 
for d in soup.find_all("driver"):
    print(d)