为什么我的程序在外壳中没有显示嵌套的if和else？

Question

仍然不知道为什么格兰德会完全通过，而高管和初级不会呢？ 我试过删除返回值，但是这会使if语句相互碰到。

    def main(): # program is too ask subject about the hotel room he wants
    yes = "yes"    #Also calculate the cost of it 
    yes1 = "yes "
    no = "no"
    no1 = "no "
    discount = .2
    print("Welcome to Flappies Hotel!")
    print("With a *three* night stay we will take 20% off your purchase.") 
    print("The suites we have available are the Junior, Executive, and Grande.")
    print("The Grande suite runs at 350.00 a night.")
    grande = input("Would you like the Grande suite? ")
    if grande == yes or yes1 : #yes1 incase the user puts a space after the yes
        grande = 350.00
    else:
        grande1 = int(float(input("How many nights do you intend to stay? ")))
        grande2 = (grande*grande1)
        if grande1 == 3.0 :
            grande_total = (grande*grande1*discount)
            grande = float(grande2-grande_total)
            grande_fin = format(grande, '.2f')
            print("Your total purchase will be",grande_fin,",enjoy your stay at Flappies.")
            return #used to cut off the if statement so it wont continue on
        else:  
            grande = 350.00  
            grande_total = float(grande*grande1)
            grande_fin = format(grande_total, '.2f')
            print("Your total purchase will be",grande_fin,",enjoy your stay at Flappies.")
            return


    print("The Executive suite runs 250.00 a night.")
    executive = input("Would you like the Executive suite? ")
    yes = "yes"
    yes1 = "yes "
    no = "no"
    no1 = "no "
    discount = .2 
    if executive == yes or yes1 :
        executive = 250.00
    else:
        executive1 = int(float(input("How many nights do you intend to stay? ")))
        executive2 = (executive*executive1)
        if executive1 == 3.0 :
            executive_total = (executive*executive1*discount)
            executive = float(executive2-executive_total)
            executive_fin = format(executive, '.2f')
            print("Your total purchase will be",executive_fin,",enjoy your stay at Flappies.")
            return
        else:
            executive = 250.00
            executive_total = float(executive*executive1)
            executive_fin = format(executive_total, '.2f')
            print("Your total purchase will be",executive_fin,",enjoy your stay at Flappies.")
            return        

    print("The Junior suite runs 150.00 a night.")
    junior = input("Would you like the Junior suite? ")
    if junior == yes or yes1 :
        junior = 150.00
    else:
        junior1 = int(float(input("How many nights do you intend to stay? ")))
        junior2 = (junior*junior1)
        if junior1 == 3.0 :
            junior_total = (junior*junior1*discount)
            junior = float(junior2-junior_total)
            junior_fin = format(junior, '.2f')
            print("Your total purchase will be",junior_fin,",enjoy your stay at Flappies.")
            return
        else:
            junior = 150.00
            junior_total = float(junior*junior1)
            junior_fin = format(junior_total, '.2f')
            print("Your total purchase will be",junior_fin,",enjoy your stay at Flappies.")
            return

main()

我只是不明白为什么它不起作用我感到困惑，我在空闲状态下运行它，不会表现出高管和初级，但会轻松地升入年级？

Answer 1

if grande == yes or yes1:被解析为if (grande == yes) or (yes1):则始终为true，因为yes1是一个非空字符串（在布尔测试中具有真值），因此正确的测试将是if grande == yes or grande == yes1:

现在，有一种更好的方法来处理这种情况：在测试之前将用户的输入标准化：

grande = input("Would you like the Grande suite? ")
# .strip() : remove all whitespaces
# .lower() : convert to lowercase
grande = grande.strip().lower()

if grande == yes:
   # etc