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[英]How to parse list of JSON objects surrounded by [] using Retrofit and GSON?
[英]How can I parse JSON Array Using Retrofit and GSON?
我已经学习了如何通过Retrofit Gson解析JSON对象,但是我需要通过Retrofit Gson解析完整的JSON数组。
我需要解析以下内容:
"{\n" +
" \"snappedPoints\": [\n" +
" {\n" +
" \"location\": {\n" +
" \"latitude\": -35.2784167,\n" +
" \"longitude\": 149.1294692\n" +
" },\n" +
" \"originalIndex\": 0,\n" +
" \"placeId\": \"ChIJoR7CemhNFmsRQB9QbW7qABM\"\n" +
" },\n" +
" {\n" +
" \"location\": {\n" +
" \"latitude\": -35.280321693840129,\n" +
" \"longitude\": 149.12908274880189\n" +
" },\n" +
" \"originalIndex\": 1,\n" +
" \"placeId\": \"ChIJiy6YT2hNFmsRkHZAbW7qABM\"\n" +
" },\n" +
" {\n" +
" \"location\": {\n" +
" \"latitude\": -35.280960897210818,\n" +
" \"longitude\": 149.1293250692261\n" +
" },\n" +
" \"originalIndex\": 2,\n" +
" \"placeId\": \"ChIJW9R7smlNFmsRMH1AbW7qABM\"\n" +
" },\n" +
" {\n" +
" \"location\": {\n" +
" \"latitude\": -35.28142839817933,\n" +
" \"longitude\": 149.1298619971291\n" +
" },\n" +
" \"originalIndex\": 3,\n" +
" \"placeId\": \"ChIJy8c0r2lNFmsRQEZUbW7qABM\"\n" +
" },\n" +
" {\n" +
" \"location\": {\n" +
" \"latitude\": -35.28193988170618,\n" +
" \"longitude\": 149.13001013387623\n" +
" },\n" +
" \"originalIndex\": 4,\n" +
" \"placeId\": \"ChIJ58xCoGlNFmsRUEZUbW7qABM\"\n" +
" },\n" +
" {\n" +
" \"location\": {\n" +
" \"latitude\": -35.282819705480151,\n" +
" \"longitude\": 149.1295597114644\n" +
" },\n" +
" \"originalIndex\": 5,\n" +
" \"placeId\": \"ChIJabjuhGlNFmsREIxAbW7qABM\"\n" +
" },\n" +
" {\n" +
" \"location\": {\n" +
" \"latitude\": -35.283139388422363,\n" +
" \"longitude\": 149.12895618087012\n" +
" },\n" +
" \"originalIndex\": 6,\n" +
" \"placeId\": \"ChIJ1Wi6I2pNFmsRQL9GbW7qABM\"\n" +
" },\n" +
" {\n" +
" \"location\": {\n" +
" \"latitude\": -35.284728724835304,\n" +
" \"longitude\": 149.12835061713685\n" +
" },\n" +
" \"originalIndex\": 7,\n" +
" \"placeId\": \"ChIJW5JAZmpNFmsRegG0-Jc80sM\"\n" +
" }\n" +
" ]\n" +
"}"
我只需要纬度和经度。
这是我知道的通过翻新GSON解析JSON对象的方法
package com.example.akshay.retrofitgson;
import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;
/**
* Created by Akshay on 9/6/2015.
*/
public class gitmodel {
@SerializedName("latitude")
@Expose
public String latitude;
@SerializedName("longitude")
@Expose
public String longitude;
public void setLatitude(String latitude)
{
this.latitude = latitude;
}
public String getLatitude()
{
return latitude;
}
public void setLongitude(String longitude)
{
this.longitude = longitude;
}
public String getlatitude()
{
return latitude;
}
}
Retrofit使用Gson库来序列化Json响应。 只要正确设置了模型类,就可以告诉Gson尝试将json序列化为该模型类的实例。 您的代码应类似于以下内容:
String json; // retrieved from file/server
MyObject myObject = new Gson().fromJson(json, MyObject.class)
您可能只需要纬度/经度,但是最简单的方法是设置POJO以获取所有内容,然后从POJO中提取纬度/经度。 如果需要,您甚至可以设计反序列化的对象以隐藏内部对象。 对于您的JSON,这非常简单,只需执行以下操作:
public static class SnappedPoints {
private List<Point> snappedPoints;
public String toString() {
return snappedPoints.toString();
}
}
public static class Point {
private Location location;
public double getLatitude() {
return location.getLatitude();
}
public double getLongitude() {
return location.getLongitude();
}
public String toString() {
return "{" + location.getLatitude() + "," + location.getLongitude() + "}";
}
}
public static class Location {
double latitude;
double longitude;
public double getLatitude() {
return latitude;
}
public double getLongitude() {
return longitude;
}
}
您只需执行以下操作即可看到实际效果:
public static void main(String[] args) {
System.out.println(new Gson().fromJson(json, SnappedPoints.class));
}
或者,在翻新的情况下,如下所示:
public interface MyRetrofitAPI {
@GET("/path/to/json")
void getSnappedPoints(/* arguments */, Callback<SnappedPoints> callback);
}
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