MySQL十进制不返回结果

Question

桌子：

mysql> describe tbl_affiliate_commissions;
+-------------------+---------------+------+-----+---------+----------------+
| Field             | Type          | Null | Key | Default | Extra          |
+-------------------+---------------+------+-----+---------+----------------+
| id                | int(255)      | NO   | PRI | NULL    | auto_increment |
| sale_minimum      | decimal(10,2) | NO   |     | NULL    |                |
| sale_maximum      | decimal(10,2) | NO   |     | NULL    |                |
| commission_amount | decimal(10,2) | NO   |     | NULL    |                |
+-------------------+---------------+------+-----+---------+----------------+
4 rows in set (0.01 sec)

价值观：

mysql> select * from tbl_affiliate_commissions;
+----+--------------+--------------+-------------------+
| id | sale_minimum | sale_maximum | commission_amount |
+----+--------------+--------------+-------------------+
|  1 |         0.00 |        99.99 |              5.00 |
|  2 |       100.00 |       249.99 |             10.00 |
|  3 |       250.00 |       499.99 |             20.00 |
|  4 |       500.00 |       749.99 |             35.00 |
|  5 |       750.00 |       999.99 |             50.00 |
|  6 |      1000.00 |      1999.99 |             75.00 |
|  7 |      2000.00 |      3999.99 |            100.00 |
|  8 |      4000.00 |     10000.00 |            300.00 |
+----+--------------+--------------+-------------------+
8 rows in set (0.00 sec)

询问：

SELECT * FROM `tbl_affiliate_commissions` 
WHERE sale_minimum >= '359.80' 
AND sale_maximum <= '359.80'

运行此查询返回零结果。 如果您在没有另一个的情况下运行“WHERE”语句，则会返回结果。 为什么会这样？

Answer 1

你的条件表达式是倒退的。 尝试这个：

SELECT *
FROM `tbl_affiliate_commissions` 
WHERE sale_minimum <= 359.80 AND sale_maximum >= 359.80;

或者，尝试BETWEEN ：

SELECT *
FROM `tbl_affiliate_commissions` 
WHERE 359.80 BETWEEN sale_minimum AND sale_maximum;