mySql 返回不正确的结果

Question

我有一个查询

SELECT date, SUM(cimpression) AS cimp, SUM(cclick) AS cclick 
FROM stdaily 
WHERE date BETWEEN :start AND :end 
AND (id = 21 AND id = 32 AND id = 12 AND id = 33)
GROUP BY date
ORDER BY date ASC;

此查询只需要返回 id 等于 21、32、12 和 33 的结果，但返回不包含这些特定 ID 的结果，不确定到底是什么问题？ 有什么建议吗？

Answer 1

我认为您正在寻找的是：

SELECT date,SUM(cimpression) AS cimp, SUM(cclick) AS cclick
FROM stdaily
WHERE date BETWEEN :start AND :end 
AND id in (21, 32, 12, 33) 
GROUP BY date 
ORDER BY date ASC;

这将返回结果，其 id in括号中包含的任何结果相同。

Answer 2

您的查询不正确，因为 ID 不能同时包含所有这些值：

id = 21 AND id = 32 AND id = 12 AND id = 33 

前面的条件不成立，结果是NULL。

尝试这个：

id = 21 OR id = 32 OR id = 12 OR id = 33 

Answer 3

id = 21 AND id = 32 AND id = 12 AND id = 33 

应该

id = 21 OR id = 32 OR id = 12 OR id = 33 

Answer 4

您没有指定他应该在哪里检查这些 id，并且您传递 id 的方式也是错误的

WHERE date BETWEEN :start AND :end AND (id = 21 AND id = 32 AND id = 12 AND id = 33 )

它应该是这样的：

SELECT date,SUM(cimpression) AS cimp,SUM(cclick) AS cclick 
FROM stdaily 
WHERE date BETWEEN :start AND :end AND id IN (21, 32, 12, 33 ) 
GROUP BY date 
ORDER BY date ASC

Answer 5

我不知道您的数据是如何构造的，但我很惊讶这会返回任何结果。 id 怎么可能同时是 21 和 32？ 例如，如果我使用

SELECT * FROM users WHERE 1=1 AND (id = 10 AND id = 11);

即使有 id 为 10 和 11 的用户，我也不会得到结果。

您应该使用 OR 或更好的 IN(21,32,12,33)