[英]C Programming input error with scanf skipping
我正在介绍C编程课程,我有点困惑。 我的输入无法正常工作。 当我运行该程序时,该程序将接受第一个输入,然后跳过其余的输入提示,并生成总计。
到底是怎么回事? 我完全迷路了。
int main(void) {
/* declarations: */
double y, m1, s1, s2, m2, i;
char g; /* Do not remove this line */
/*Print the title of the program*/
printf(" MILEAGE SPEED INTERPOLATION\n");
printf("______________________________________________________________________\n");
printf("Enter in your first speed:\n"); //this is s1
scanf("%.1f", &s1);
printf("Enter in your mileage:\n"); //m will be mileage 1
scanf("%.1f", &m1); //mileage is y
printf("Enter in your second speed:\n"); //this is s2
scanf("%.1f", &s2);
printf("Enter in your second mileage:\n");
scanf("%.1f", &m2);
/*Get the needed input*/
/*get the interpolation from the user*/
printf("Enter your interpolation:\n"); //number between 1 and 2
scanf("%.lf", &i);
printf("______________________________________________________________________\n");
/*Statements that perform the desired task*/
// This equation is calculating from rpm to knots
y = m1 + (i - s1) * (m2 - m1) / (s2 - s1); //This will do the equation for us.
/* Printing of the results*/
// Trying to print the answer from above equation
printf("Your estimated value is %f: ", y);
/*Keeps the window open. Please do not alter this.*/
printf("\n\nEnter to q to quit.\n");
do {
g = getchar();
} while (g != 'q');
return 0;
}
您必须使用"%lf"
的double
用scanf()
if (scanf("%lf", &s1) != 1)
return -1; /* Bad input */
并且您不能指定精度,而是可以指定最大字符数。
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