繁体   English   中英

scanf函数正在C编程中跳过for循环中的输入

[英]scanf function is skipping input in for loop in C Programming

我已经使用结构方法编写了简单的代码,在该代码中,我使用3个学生的for循环将string(name)用作输入。 对于第一次迭代,for循环中的每一行都应按预期方式工作。...但是问题出在第二次迭代中……在第二次迭代中scanf跳过了字符串(名称)的输入...

我的代码如下:

#include<stdio.h>

struct student_data
{
    char name[5];
    int dsd;
    int dic;
    int total;  
};

void main()
{
    struct student_data s[3];


    int i;

    for(i = 0;i<3;i++)
    {
        printf("Enter Name of Student\n");
        scanf("%[^\n]",s[i].name);         // Problem occures here in     
                                       //  second iteration  

        printf("\nEnter marks of DSD\n");
        scanf("%d",&s[i].dsd);

        printf("Enter marks of DIC\n");
        scanf("%d",&s[i].dic);


        s[i].total = s[i].dsd+s[i].dic;     

    }

    printf("%-10s %7s %7s  %7s\n ","Name","DSD","DIC","Total");
    for(i=0;i<3;i++)
    {

       printf("%-10s %5d  %6d      %6d\n",s[i].name,s[i].dsd,s[i].dic,s[i].total);
}  

}

代码的主要问题是,您定义了student_data s[2] ,它是一个大小为2的数组,但是在循环中,您正在循环for (i=0; i<3; i++) ,该数组对数组有效大小为3。此较小的修改可以正常工作:

 int main()
{
struct student_data s[2];  // array of size 2


int i;

for(i=0; i<2; i++)      // i will have values 0 and 1 which is 2 (same as size of your array)
{
    printf("Enter Name of Student\n");
    scanf("%s", s[i].name);

    printf("\nEnter marks of DSD\n");
    scanf("%d", &s[i].dsd);

    printf("Enter marks of DIC\n");
    scanf("%d", &s[i].dic);

    s[i].total = s[i].dsd+s[i].dic;

}

    printf("%-10s %7s %7s  %7s\n ","Name","DSD","DIC","Total");

    for(i=0; i<2; i++)   // same mistake was repeated here
    {
        printf("%-10s %5d  %6d     %6d\n",s[i].name,s[i].dsd,s[i].dic,s[i].total);
    }
return 0;
}

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM