[英]Pass a type as parameter to method
我有一个叫做RootObject
的类:
public class RootObject
{
public string Name { get; set; }
public int Age { get; set; }
public int Address { get; set; }
}
public void getdata()
{
WebRequest request = WebRequest.Create("http://addresstojson.com/json.json");
WebResponse response = await request.GetResponseAsync();
using (var stream = new StreamReader(response.GetResponseStream()))
{
json = JsonConvert.DeserializeObject<RootObject>(stream.ReadToEnd());
}
}
在getdata()
方法的最后一条语句中,传递类型:
JsonConvert.DeserializeObject</*here*/>(Stream.ReadToEnd())
我想将类型作为参数传递给getdata(RootObject)
方法。
有没有办法在C#中使用泛型呢?
实现强类型反序列化的标准方法是:
public T Get<T>()
{
string json = ...; // get data somehow
return JsonConvert.DeserializeObject<T>(json);
}
看起来您想异步读取结果,因此您实际上需要将结果作为Task<T>
,并使用读取数据的方法的xxxxAsync
版本:
public Task<T> GetData<T>()
{
WebRequest request = WebRequest.Create("http://addresstojson.com/json.json");
using (WebResponse response = await request.GetResponseAsync())
{
using(var stream = new StreamReader(response.GetResponseStream()))
{
string json = await stream.ReadToEndAsync();
T result = JsonConvert.DeserializeObject<T>();
return result;
}
}
}
您可以在此处了解有关泛型的更多信息: https : //msdn.microsoft.com/zh-cn/library/512aeb7t.aspx
public static async Task<T> GetData<T>(string add)
{
WebRequest request = WebRequest.Create(add);
WebResponse response = await request.GetResponseAsync();
using (var stream = new StreamReader(response.GetResponseStream()))
{
return JsonConvert.DeserializeObject<T>(stream.ReadToEnd());
}
}
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