不发送套接字时，Java“ NotSerializableException：java.net.Socket”

Question

因此，我通过以下线程将Server对象发送到客户端：

public ConnectionThread(final Server server) {
    super(new Runnable() {
        public void run() {
            try {
                Socket client = server.serverSocket.accept();
                server.clients.add(client);

                ObjectInputStream in = new ObjectInputStream(
                        client.getInputStream());
                ObjectOutputStream out = new ObjectOutputStream(
                        client.getOutputStream());

                System.out.println("Connected client: "
                        + client.getRemoteSocketAddress());
                server.launchNewThread();

                Object input;
                while (!client.isClosed()) {
                    input = in.readObject();

                    if (input != null) {
                        if (input.toString().equals("server")) {
                            out.writeObject(server);
                        }
                    }
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    });

当我调用out.writeObject（server）时，出现以下异常：

java.io.NotSerializableException: java.net.Socket

这是Server类：

public class Server implements Serializable {
private static final long serialVersionUID = 4634111951586948020L;

public ServerArgs args;

public ArrayList<Socket> clients = new ArrayList<Socket>();
public ServerSocket serverSocket;

public Server(int port) throws IOException {
    serverSocket = new ServerSocket(port);

    launchNewThread();
}

public void launchNewThread() {
    ConnectionThread thread = new ConnectionThread(this);
    thread.start();
}

public static void main(String[] args) throws IOException {
    new Server(27015);
}
}

Answer 1

public ArrayList<Socket> clients = new ArrayList<Socket>();
public ServerSocket serverSocket;

您那里有很多不可序列化的套接字。 尚不清楚“发送服务器”的目的是什么，但也许您应该只发送ServerArgs或将这两个字段标记为transient 。