[英]How to find text between less and greater than, then strip the <> in Java?
我不知道如何找到这些单词..例子我有这个文字......
The other day I went to the <location> and bought some <plural-noun> . Afterwards, I went to <location> , but it was very <adjective> so I left quickly and went to <location> .
当我在谷歌搜索<
和>
时,我不知道搜索的原因,它将被忽略。 需要帮助如何获得此字符串。
所以我会得到<location>
, <plural-noun>
, <location>
, <adjective>
, <location>
我必须使用charAt()
方法。 我的尝试:
String string = this.fileName;
for(int i = 0; i < string.length(); i++)
if((string.charAt(i) == '<') && (string.charAt(i) == '>'))
System.println(""); //<-------- IM STUCK HERE
我不知道......差不多两天没睡觉了。
我目前但最后一个问题......如何删除显示中每个单词的<
和>
?
String string = this.template;
Pattern pattern = Pattern.compile("<.*?>");
Matcher matcher = pattern.matcher(string);
List<String> listMatches = new ArrayList<String>();
while(matcher.find()) {
listMatches.add(matcher.group());
}
// System.out.println(listMatches.size());
int indexNumber = 1;
for(String s : listMatches) {
System.out.println(Integer.toString(indexNumber) + ". " + s);
indexNumber++;
}
您可以使用Pattern
和Matcher
类。
<.*?>
。 这里真的有两个问题,所以我只回答最后一个问题; 如果你有你想要的<text>
,那就这样:
String text = "<the_text_you_want>";
text.replace("<","").replace(">","").replace("-"," ");
这将摆脱分界符。
读取整行并将其存储在String line
。 然后,使用:
String line = "The other day I went to the <location> and bought some <plural-noun> . Afterwards, I went to <location> , but it was very <adjective> so I left quickly and went to <location> .";
boolean found = false;
String data[] = new String[20];
int counter = 0;
Arrays.fill(data, "");
for(int i = 0; i < line.length() && counter < 20; i++) {
if(line.charAt(i) == '<')
found = true;
else if(line.charAt(i) == '>' && found) {
found = false;
counter++;
}
else if(found) {
data[counter] += line.charAt(i);
}
}
for(int i = 0; i < counter; i++)
System.out.println("Scanned data #" + (i + 1) + " = " + data[i]);
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