Java中double 0.0是否大于或小于0

Question

我想请更多澄清。 这是我的示例程序

double diff = 7.500 - 7.500;
System.out.println(diff); // result 0.0
if (diff > 0) {
    System.out.println("+" + diff ); //result +0.0
} else {
    System.out.println("-" + diff ); //result -0.0
}

我的结果是-0.0 。 我的期望是0 == 0.0，然后跳过其他情况。 但是它进入了else条件.double 0.0是大于还是小于0？

Answer 1

请注意，您正在检查diff> 0-如果它为零，则在打印-0.0

Answer 2

在您的情况下，使用（更大） >将0.0与0进行比较，因此0.0并非严格大于0（等于）。 然后，您的程序转到else部分。

if(diff == 0 ) {
    System.out.println("+" + diff ); //result 0.0
} else if (diff > 0) {
    System.out.println("+" + diff ); //result +diff
} else { // diff is less than 0 
    System.out.println("-" + diff ); //result -diff
}

Answer 3

这是我的答案：

double diff = 7.500 - 7.500;
    System.out.println(diff);

    if(diff>0){
        System.out.println("+"+diff);
    }else if(diff<0){
        System.out.println("-"+diff);
    }else if(diff==0){
        System.out.println("="+diff);
    }
}

我的结果是这样的：
0.0
= 0.0

您必须忘记0.0等于0是'else the 0.0> 0'以外的'0.0> = 0'