Double Count Select返回错误结果

Question

您好，我正在使用以下查询来显示行数，其中id是第一个表中的相同数字，我还有2个表。 如果我只留下一个计数，那么一切都可以正常工作，但是如果选择了两次计数，我将得到相同的结果，这是错误的：

'SELECT c.*, count(s.userID) as count_consulta, count(a.userID) as count_asesoria
   FROM users as c 
   LEFT JOIN consulta AS s ON s.userID = c.userID 
   LEFT JOIN asesoria AS a ON a.userID = c.userID
   GROUP BY c.userID DESC'

有了这个我得到：

count_consulta = 15
count_asesoria = 15

应该在哪里

count_consulta = 3
count_asesoria = 5

任何帮助都将受到欢迎。 谢谢！

Answer 1

有了“将欢迎任何帮助”的说法，我将其扔在那里，看看它是否符合您的意思。

$sql="select *,
    ( select count( distinct s.`userID` ) from `consulta` ) as 'count_consulta',
    ( select count( distinct a.`userID` ) from `asesoria` ) as 'count_asesoria'
    from `users` c
        left outer join `consulta` s on s.`userID`=c.`userID`
        left outer join `asesoria` a on a.`userID`=c.`userID`
    group by c.`userID` desc;";