[英]SQL: Select the minimum of a subquery and grouping
我有一些在MySQL DB中签入和签出人员的记录:
SELECT * FROM db
结果:
-----------------------------------------------------------------------
ID Name Lastname in out
1 James Bond 20151014090000 20151014103000
2 James Bond 20151014110000 20151014123000
3 James Bond 20151014130000 20151014143000
4 James Bond 20151014150000 20151014163000
5 James Bond 20151014170000 20151014183000
6 James Bond 20151014190000 20151014203000
7 Jason Bourne 20151014090000 20151014103000
8 Jason Bourne 20151014110000 20151014123000
9 Jason Bourne 20151014130000 20151014143000
10 Jason Bourne 20151014150000 20151014163000
11 Jason Bourne 20151014170000 20151014183000
12 Jason Bourne 20151014190000 20151014203000
13 Jack Bauer 20151014090000 20151014103000
14 Jack Bauer 20151014110000 20151014123000
15 Jack Bauer 20151014130000 20151014143000
16 Jack Bauer 20151014150000 20151014163000
17 Jack Bauer 20151014170000 20151014183000
18 Max Payne 20151014090000 20151014103000
19 Max Payne 20151014110000 20151014123000
20 Max Payne 20151014130000 20151014143000
21 Max Payne 20151014150000 20151014163000
22 Max Payne 20151014170000 20151014183000
考虑到其中的(IN),我想获取最接近当前日期的日期,即输入。
我正在使用它与MySQL中的当前日期进行比较:
date_format(now(), '%Y%m%d%H%i%S')
假设是20151014133000
我想从查询中得到的是:
3 James Bond 20151014130000 20151014143000
9 Jason Bourne 20151014130000 20151014143000
15 Jack Bauer 20151014130000 20151014143000
20 Max Payne 20151014130000 20151014143000
致意,并非常感谢您!
[edit1] in和out是int,我正在将其与该格式的实际时间进行比较,因为使用以下操作:date_actual-in_value = time_lapsed例如:
20151014133000-20151014090000 = 43000
如果获得time_lapsed的最小值,则将获得最接近date_actual的日期,然后在DB上搜索按名称和姓氏分组的日期。
如果我理解正确,则需要:
SELECT DISTINCT `Name`, `Lastname`, MAX(IN) FROM DB
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