Python：不带CSV模块的CSV文件到字典

Question

我知道答案还有很多其他问题，但是我想知道如何将CSV文件读入嵌套字典中。 因此，它可能来自以下内容：

    '''"YEAR","GENDER","NAME","COUNT"
    "2011","FEMALE","A","100"
    "2012","FEMALE","A","50"
    "2012","FEMALE","B","10"
    "2012","FEMALE","C","10"
    "2012","FEMALE","D","5"
    "2013","FEMALE","A","1000"
    '''

对于这样的事情：

{('B', 'FEMALE'): {2012: (10, None)}, 
 ('C', 'FEMALE'): {2012: (10, None)}, 
 ('A', 'FEMALE'): {2011: (100, None), 
                   2012: (50, None), 
                   2013: (1000, None)}, 
 ('D', 'FEMALE'): {2012: (5, None)}}

但是我需要不导入任何内容来执行此操作，因此无法使用CSV模块。 这是一个一般的例子。 我需要代码可以处理多个可能比这个更长或更短的案例。

（共有11个文件，这是其中之一，这里的文本与文件中的内容完全相同：

    "YEAR","GENDER","NAME","COUNT"
    "2011","FEMALE","A","100"
    "2012","FEMALE","A","50"
    "2012","FEMALE","B","10"
    "2012","FEMALE","C","10"
    "2012","FEMALE","D","5"
    "2013","FEMALE","A","1000"

Answer 1

answer = {}
with open('path/to/file') as infile:
    infile.readline()  # we don't care about the header row
    for line in infile:
        year, gender, name, count = (s.strip('"') for s in line.split(','))
        key = (name, gender)
        if key not in answer: answer[key] = {}
        answer[key][int(year)] = (int(count), None)