[英]How to upload excel file on server(django) in angularjs?
我想在服务器上上传文件,但是在Utility Service中,调试期间未定义for循环中的变量文件 ,请检查指令是否正确。
的HTML
<input type="file" accept=".xlsx" file-model/>
<button ng-click="upload()">upload me</button>
fileModel指令
app.directive('fileModel', function () {
return {
restrict: 'A',
transclude: true,
link: function($scope, $element) {
var fileInput = $element.find('input[type="file"]');
fileInput.bind('change', function(e) {
$scope.notReady = e.target.files.length == 0;
$scope.files = [];
for (var i in e.target.files) {
if (typeof e.target.files[i] == 'object')
$scope.files.push(e.target.files[i]);
}
});
}
};
});
控制者
$scope.upload = function() {
var uploadUrl = 'someurl';
UtilityService.upload($scope.files, $scope.user, uploadUrl);
};
服务
function UtilityService($http, $rootScope) {
var service = {};
service.upload=upload;
function upload(files, user, uploadUrl) {
var formData = new FormData();
for (var i in files) {
formData.append('file_' + i, files[i]);
}
formData.append("UserId", user.id);
formData.append("UserRole", user.roles);
$http({
method: 'POST',
url: config.server +uploadUrl,
enctype: "multipart/form-data",
data: formData,
headers: {
'Content-Type': undefined,
},
transformRequest: angular.identity
})
.success(function(data, status, headers, config) {
service.data = data;
});
}
return service;
}
好吧,我想问题出在这行-var fileInput = $ element.find('input [type =“ file”]');
不知道为什么您需要找到任何东西。 $ element是此处的实际文件输入元素。
修改指令-试试这个
app.directive('fileModel', function () {
return {
restrict: 'A',
transclude: true,
link: function($scope, $element) {
var fileInput = $element;
fileInput.bind('change', function(e) {
$scope.notReady = e.target.files.length == 0;
$scope.files = [];
for (var i in e.target.files) {
if (typeof e.target.files[i] == 'object')
$scope.files.push(e.target.files[i]);
}
});
}
};
});
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