[英]Increase an array index by 1 C#
我有一个用于计数的整数数组。
将整数数组的某个索引增加1的最简单方法是什么?
我的代码目前看起来像这样。
input = Convert.ToInt32(textBox1.Text);
number1 = rand.Next(1, 7);
number2 = rand.Next(1, 7);
number3 = rand.Next(1, 7);
//array used to keep track of how many times a certain number has showed up
int[] counters = new int[14];
int sum = number1 + number2 + number3;
for (int i = 0; i <= input; i++)
{
counters[sum] = counters[sum] + 1; //counters[sum]++;???
}
for (int i = 0; i < 14; i++)
{
richTextBox1.Text += "The number " + (i + 1) + "showed up" + counters[i] + " times\n";
}
我究竟做错了什么? 我为什么不能做:
array[i]++; or array[i] = array[i] + 1; ???
编辑为清楚起见。
我正在尝试做的是:
根据用户需要将3个骰子滚动
将3个骰子相加(总和应在3 -18之间),然后记下每个和解出现的频率。
然后最后以%显示每个数字显示多少次。
您可以使用linq和List来执行此操作,请参见以下代码:
input = Convert.ToInt32(textBox1.Text);
for(var i = 0; i < input; i++)
{
number1 = rand.Next(1, 7);
number2 = rand.Next(1, 7);
number3 = rand.Next(1, 7);
//array used to keep track of how many times a certain number has showed up
int sum = number1 + number2 + number3;
sums.Add(sum); //Where sums is a List<int>
}
var report = sums.GroupBy(i => i).Select(g => new { TimesShowedUp = g.Count(), Sum = g.Key });
foreach(var r in report)
{
richTextBox1.Text += "The number " + r.Sum + "showed up" + r.TimesShowedUp + " times\n";
}
听起来您真正想要的是以下内容。
Random rand = new Random();
int numberOfRolls = Convert.ToInt32(textBox1.Text);
int[] counters = new int[16]; //16 different possible sums (3 to 18)
for (int i = 0; i < numberOfRolls; i++)
{
int sum = rand.Next(1, 7) + rand.Next(1, 7) + rand.Next(1, 7);
counters[sum - 3]++;
}
for (int i = 0; i < 16; i++)
{
richTextBox1.Text += "The number " + (i + 3) + " showed up " + counters[i] + " times\n";
}
这需要从textBox1
滚动的次数,然后循环该次数,以3个随机数(1-6)创建一个sum
。 并增加数组中的相应位置。 由于存在16种可能性,因此将数组初始化为该大小,并且在打印时只需将3减去即可从总和转换为索引,然后加3即可将其转换回来。
//array used to keep track of how many times a certain number has showed up
int[] counters = new int[15];
iterations = Convert.ToInt32(textBox1.Text);
for (int i = 1; i <= iterations; i++)
{
number1 = rand.Next(1, 7);
number2 = rand.Next(1, 7);
number3 = rand.Next(1, 7);
int sum = number1 + number2 + number3;
counters[sum-3]++;
}
for (int i = 0; i <= 15; i++)
{
richTextBox1.Text += "The number " + (i + 3) + " showed up " + counters[i] + " times\n";
}
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