在单元测试中使用mock来修补sleep

Question

我有一段代码放在这样的模块中：

MyWorker.py：

from gevent import sleep

class MyWorker(object):
  def run(self):
    for _ in range(10):
      do_something()
      sleep(1)

然后我想在嘲笑睡觉时测试这个。 我尝试了多种方法，但都失败了。 我认为应该工作的一种方式：

from mock import patch
from x.y.z.MyWorker import MyWorker

class TestWorker(unitest.testCase):
  def Test_my_worker(self):
    with patch('x.y.z.MyWorker.sleep'):
      a = MyWorker()
      a.run()

Answer 1

我尝试了一些，结果很简单：修改from xyzMyWorker import MyWorker from xyzMyWorker import MyWorker, sleep ，或者你可以from xyzMyWorker import *和所有单元测试工作。 上面的评论给了我这个想法。

这就是我最终做的事情：

from x.y.z.MyWorker import MyWorker, sleep

Class TestMyWorker(unittest.TestCase):

  def setUp(self):
    self.patcher = patch('x.y.z.MyWorker.sleep')
    self.patcher.start()

  def tearDown(self):
    self.patcher.stop()

  def Test_my_worker_success():
    MyWorker().run()

  def Test_my_worker_fail():
    ...

Answer 2

这是嘲笑的睡眠的完整工作版本

# TestMyWorker.py
#!/usr/bin/python
import unittest
import mock

# myWorker.py MyWorker(class)
from myWorker import MyWorker

class TestWorker(unittest.TestCase):

    # myWorker.py - mock away sleep
    @mock.patch('myWorker.sleep')
    def test_my_worker(self, mock_sleep):
        # mock away the sleep()
        mock_sleep.return_value = False
        worker = MyWorker()
        # should run witout calling sleep()
        worker.run()
        self.assertFalse(mock_sleep.sleep.called,"Fail - sleep really called!")

if __name__ == '__main__':
    suite = unittest.TestLoader().loadTestsFromTestCase(TestWorker)
    unittest.TextTestRunner(verbosity=2).run(suite)