如何从（AB）点迅速获得价值

Question

我有这种字符串：“ POINT(101.650577657408 3.1653186153213) ”。

任何人都知道如何从此String中获得POINT的第一个和第二个值？

Answer 1

您可以使用componentsSeparatedByString函数轻松地将字符串吐出。

let myStr = "POINT(101.650577657408 3.1653186153213)"
let characterSet = NSCharacterSet(charactersInString: "( )")
var splitString = myStr.componentsSeparatedByCharactersInSet(characterSet)
print(splitString[0])
print(splitString[1])
print(splitString[2])

仅当您具有完整的一个String时，以上方法才有效。

Answer 2

尽管NSCharacterSet解决方案是正确的，但这是使用功能最强大的正则表达式的另一种解决方案。

var error: NSError?

// Initialise the regex for a float value
let regex: NSRegularExpression = NSRegularExpression(pattern: "(\\d*\\.\\d*)", options: NSRegularExpressionOptions.CaseInsensitive, error: &error)! 

// Matches array contains all the match found for float in given string
let matches: NSArray = regex.matchesInString(str as String, options: NSMatchingOptions.ReportProgress, range: NSMakeRange(0, str.length))

// You can easily get all values by enumeration
for match in matches {
    println(str.substringWithRange(match.range))
}

此解决方案的好处是它将扫描所有浮点值，并且在更改模式时也可以使用。

Answer 3

试试这个，这将适合您的字符串

    let myStr = "POINT(101.650577657408 3.1653186153213)"
    let strWithout_POINT_openingBrace = myStr.stringByReplacingOccurrencesOfString("POINT(", withString: "")//"101.650577657408 3.1653186153213)"
    let strWithout_closingBrace = strWithout_POINT_openingBrace.stringByReplacingOccurrencesOfString(")", withString: "")//"101.650577657408 3.1653186153213"
    //now you have only space between two values
    //so split string by space
    let arrStringValues = strWithout_closingBrace.componentsSeparatedByString(" ");//["101.650577657408","3.1653186153213"]

    print(arrStringValues[0]);//first value "101.650577657408"
    print(arrStringValues[1]);//second value "3.1653186153213"