Swift iOS-将数组过滤为类似对象的数组

Question

我有一个带有子对象的对象数组。

我想基于子对象将数组排序为数组的数组

例如：的数组

[employee, employee, employee, employee]

现在我想做的就是这样排序->

[[employee.job.jobName = "baker",employee.job.jobName = "baker"],
[employee.job.jobName = "sweeper",employee.job.jobName = "sweeper"]]

目标是创建一个表格视图，其中节标题将其job.jobName相同的员工分组。 并且这些行将由这些雇员，他们的姓名等组成。为此，我需要一个组成部分数的雇员的唯一的job.jobNames数组，然后每个部分中的雇员数组组成行数。

我曾尝试使用array.map和array.filter，但我想我需要一种组合，但我似乎无法解决这个问题。 任何帮助将不胜感激！

Answer 1

这是我如何将员工数组拆分为数组的看法。

// Just needed to make the example work
struct Job {
    var name: String
}

struct Employee {
    var job: Job
}
/////////////////////////////////////////

let employees = [Employee(job: Job(name: "baker")), Employee(job: Job(name: "sweeper")), Employee(job: Job(name: "baker")), Employee(job: Job(name: "sweeper"))]

var jobs = Set<String>()

employees.forEach { jobs.insert($0.job.name) }

let sortedJobs = jobs.sort()

var groupedEmployees = [[Employee]]()
for jobName in sortedJobs {
    groupedEmployees.append(employees.filter({ $0.job.name == jobName }))
}

print(groupedEmployees)

产生期望的输出：

[[main.Employee(job: main.Job(name: "baker")), main.Employee(job: main.Job(name: "baker"))], [main.Employee(job: main.Job(name: "sweeper")), main.Employee(job: main.Job(name: "sweeper"))]]

Answer 2

import UIKit

/*Data Structure for Employee*/
class Employee:NSObject{
    /*Unemployed for default*/
    var job:String = "unemployed"

    init(job:String){
        self.job = job
    }

    override var description: String {
       return self.job
    }
}



/**Returns the array of arrays of enmployees sorted by jobs*/
func sortEmployees(employees:[Employee])->[[Employee]]
{
    //Sorting them by job
    let sorted = employees.sort({$0.job < $1.job})

    //Empty array of arrays
    var sortedEmployees = [[Employee]]()

    //job key
    var currentKey = ""
    for emp in sorted{
        let tempKey = emp.job
        //first element - edge case
        if sortedEmployees.count == 0
        {
            currentKey = tempKey
            sortedEmployees.append([emp])
        }
        else{
            if tempKey != currentKey{
                //create a new object
                sortedEmployees.append([emp])
                currentKey = tempKey
            }
            else{
                //get last array
                if let  lastArray = sortedEmployees.last{

                    var tempLast = lastArray
                    tempLast.append(emp)
                    sortedEmployees.removeLast()

                    sortedEmployees.append(tempLast)
                }
            }
        }
    }

    print(sortedEmployees)
    return sortedEmployees
}


/**Sample iVars*/
let emp1 = Employee(job: "baker")
let emp2 = Employee(job: "baker")
let emp3 = Employee(job: "sweeper")
let emp4 = Employee(job: "sweeper")


//Array with all of them
let array = [emp1, emp2, emp3, emp4]


let result = sortEmployees(array)
print(result)