如何将数组与构造函数结合使用？

Question

我目前正在制作一个抑郁症模拟程序，在其中创建了具有多个参数的Human对象，这些参数会改变抑郁症影响它们的方式。

我的问题是我能够创建单个人类对象，例如
Human steve = new Human("Steve", 25, 'm', 97000, 1, 3, false, false, 1, Human.happiness); 但是我不知道如何创建包含单个Human具有的参数的Human数组。 例如，我可以创建一个Human数组Human[] test = new Human[3]; 其中包含3个人，但我不知道如何为这些个人提供参数。

import java.util.ArrayList;

public class Human {
    private String name; // your name
    private int age; // how old you are
    private int wealth; // your average yearly income
    private int amtFriendsFamily; // how many friends/family members you are
                                    // close to
    private int levelOfEducation; /*
                                     * 1 = no education, 2 = high school
                                     * education, 3 = college education, 4 =
                                     * upper level college education
                                     */
    private boolean married;
    private boolean seeksDoctor; // true = seeks a doctor, false = does not seek
                                    // a doctor
    private char sex; // m = male, f = female
    private int race; // 1 = white, 2 = black, 3 = hispanic, 4 = asian, 5 =
                        // mideast
    static int happiness = 75;

    private String sSex, sMarried, sDoct, sRace, sEdu;
    private String[] names = { "Sally", "Karl", "Steven", "Emily" };

    public Human(String name1, int age1, char sex1, int wealth1, int amtFriendsFamily1, int levelOfEducation1,
            boolean married1, boolean seeksDoctor1, int race1, int happiness1) {
        name = name1;
        age = age1;
        wealth = wealth1;
        amtFriendsFamily = amtFriendsFamily1;
        levelOfEducation = levelOfEducation1;
        married = married1;
        seeksDoctor = seeksDoctor1;
        sex = sex1;
        race = race1;
        happiness = happiness1;

        if (sex == 'm')
            sSex = "male";
        else if (sex == 'f')
            sSex = "female";
        else
            sSex = "foreign gender";

        if (married == false)
            sMarried = "is not married, ";
        else
            sMarried = "is married, ";

        if (seeksDoctor == false)
            sDoct = "does not seek doctors.";
        else
            sDoct = "seeks doctors.";

        if (race == 1)
            sRace = "White";
        else if (race == 2)
            sRace = "Black";
        else if (race == 3)
            sRace = "Hispanic";
        else if (race == 4)
            sRace = "Asian";
        else if (race == 5)
            sRace = "Middle Eastern";

        if (levelOfEducation == 1)
            sEdu = " has no formal education, ";
        else if (levelOfEducation == 2)
            sEdu = " has a high school education, ";
        else if (levelOfEducation == 3)
            sEdu = " has a college education, ";
        else if (levelOfEducation == 4)
            sEdu = " has an upper-college level or higher education, ";

        System.out.println(name + " is a " + age + " year old " + sRace + " " + sSex + " who makes $" + wealth
                + " per year," + " has " + amtFriendsFamily + " friends and family members combined," + sEdu + sMarried
                + "and " + sDoct);
    }
}

Answer 1

你可以做这样的事情

// doesn't need size in initialization, the compiler can count the number of new Human instances 
Human[] test = new Human[] {
    new Human(...), new Human(...), new Human(...)
}

或使用索引

Human[] test = new Human[3];
test[0] = new Human(...);

Answer 2

我认为您正在寻找的是以下路线：

Human[] test = new Human[3];
Human temp = new Human("Steve", 25, 'm', 97000, 1, 3, false, false, 1, Human.happiness);
test[0] = temp;

只需为数组中的每个对象重新定义temp ，然后将数组中的一个对象设置为temp 。 当然，最好是循环执行此操作，但是在这种情况下，只有在程序为每个Human对象获取用户/文件输入的情况下，这才有可能。