[英]Sum SQL Server Count column from Grouped query
我正在尝试编写一个查询,该查询将从我的数据库中获得评分高于3星的所有内容,并根据星级平均和最高评分数返回前四个模块。 这部分效果很好。
但是为了让我将其放入图表中,我需要百分比。 因此,我需要count(id_module)
列的摘要。 我已经阅读了很多文章,并尝试实施许多解决方案,但都没有成功-有人能为我提供启示吗? 我在下面粘贴了查询并将其返回的结果-这部分工作正常...我只需要知道如何获取id模块字段的总和-在这种情况下为23 ...感谢您的帮助提供!
SELECT TOP 4
AVG(rating) AS ratingstars,
COUNT(id_module) AS countmodules,
FROM
[db]
WHERE
(rating > 3)
GROUP BY
id_module
ORDER BY
ratingstars DESC, countmodules DESC
在SQL Server 2008+中,可以使用SUM() OVER()
。 我不确定这在SQL Server 2005中是否可用。
WITH
CTE
AS
(
SELECT TOP 4
AVG(rating) AS ratingstars,
COUNT(id_module) AS countmodules
FROM [db]
WHERE (rating > 3)
GROUP BY id_module
ORDER BY ratingstars DESC, countmodules DESC
)
SELECT
ratingstars
,countmodules
,SUM(countmodules) OVER () AS SumCountModules
FROM CTE
ORDER BY ratingstars DESC, countmodules DESC
;
也许这个或一个子选择:
SELECT ratingstars, SUM(countmodules) as [countmodules] FROM
(
SELECT TOP 4 AVG(rating) AS ratingstars, COUNT(id_module) AS countmodules,FROM [db],
WHERE
(rating > 3)
GROUP BY id_module) X
GROUP BY X.ratingstars
ORDER BY X.ratingstars DESC, X.countmodules DESC
SELECT TOP 4
AVG(rating) AS ratingstars,
COUNT(*) AS countmodules,
SUM(COUNT(*)) OVER () AS allmodules /* <-- OVER () makes the double aggregate "ok" */
FROM
[db]
WHERE
rating > 3
GROUP BY
id_module
ORDER BY
ratingstars DESC, countmodules DESC
请注意,这不会将总和限制为仅前四行,因为我意识到您可能想要这样做。
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