SQL 查询中分组 COUNT 的 SUM

Question

我有一个包含 2 个字段的表：

ID  Name
--  -------
1   Alpha
2   Beta
3   Beta
4   Beta
5   Charlie
6   Charlie

我想按名称、“count”和一行“SUM”对它们进行分组

Name     Count
-------  -----
Alpha     1
Beta      3
Charlie   2
SUM       6

我将如何编写查询以在表下方添加 SUM 行？

Answer 1

SELECT name, COUNT(name) AS count
FROM table
GROUP BY name

UNION ALL

SELECT 'SUM' name, COUNT(name)
FROM table

输出：

name                                               count
-------------------------------------------------- -----------
alpha                                              1
beta                                               3
Charlie                                            2
SUM                                                6

Answer 2

SELECT name, COUNT(name) AS count, SUM(COUNT(name)) OVER() AS total_count
FROM Table GROUP BY name

Answer 3

无需指定您使用的是哪个 rdbms

看看这个演示

SQL小提琴演示

SELECT Name, COUNT(1) as Cnt
FROM Table1
GROUP BY Name
UNION ALL
SELECT 'SUM' Name, COUNT(1)
FROM Table1

也就是说，我建议总数由您的表示层添加，而不是由数据库添加。

这更像是一个使用 ROLLUP 汇总数据的 SQL SERVER 版本

SQL小提琴演示

SELECT CASE WHEN (GROUPING(NAME) = 1) THEN 'SUM'
            ELSE ISNULL(NAME, 'UNKNOWN')
       END Name, 
      COUNT(1) as Cnt
FROM Table1
GROUP BY NAME
WITH ROLLUP

Answer 4

试试这个：

SELECT  ISNULL(Name,'SUM'), count(*) as Count
FROM table_name
Group By Name
WITH ROLLUP

Answer 5

这里的所有解决方案都很棒，但不一定可以为旧的 mysql 服务器实现（至少在我的情况下）。 所以你可以使用子查询（我认为它不那么复杂）。

 select sum(t1.cnt) from 
        (SELECT column, COUNT(column) as cnt
            FROM
            table 
            GROUP BY 
            column
            HAVING 
            COUNT(column) > 1) as t1 ;

Answer 6

请按如下方式运行：

Select sum(count) 
  from (select Name, 
               count(Name) as Count 
          from YourTable
      group by Name);  -- 6

Answer 7

我解释这个问题的方式是需要每组答案的小计值。 事实证明，使用PARTITION进行小计非常容易：

SUM(COUNT(0)) OVER (PARTITION BY [Grouping]) AS [MY_TOTAL]

这是我的完整 SQL 调用的样子：

SELECT MAX(GroupName) [name], MAX(AUX2)[type],  
COUNT(0) [count], SUM(COUNT(0)) OVER(PARTITION BY GroupId) AS [total]
    FROM [MyView]
  WHERE Active=1 AND Type='APP' AND Completed=1
    AND [Date] BETWEEN '01/01/2014' AND GETDATE()
    AND Id = '5b9xxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx' AND GroupId IS NOT NULL
  GROUP BY AUX2, GroupId

从中返回的数据如下所示：

name    type    count   total
Training Group 2    Cancelation 1   52
Training Group 2    Completed   41  52
Training Group 2    No Show 6   52
Training Group 2    Rescheduled 4   52
Training Group 3    NULL        4   10535
Training Group 3    Cancelation 857 10535
Training Group 3    Completed   7923    10535
Training Group 3    No Show 292 10535
Training Group 3    Rescheduled 1459    10535
Training Group 4    Cancelation 2   27
Training Group 4    Completed   24  27
Training Group 4    Rescheduled 1   27

Answer 8

您可以使用 union 来连接行。

select Name, count(*) as Count from yourTable group by Name
union all
select "SUM" as Name, count(*) as Count from yourTable

Answer 9

对于 Sql server 你可以试试这个。

SELECT ISNULL([NAME],'SUM'),Count([NAME]) AS COUNT
FROM TABLENAME
GROUP BY [NAME] WITH CUBE

Answer 10

  with cttmp
  as
  (
  select Col_Name, count(*) as ctn from tab_name group by Col_Name having count(Col_Name)>1
  )
  select sum(ctn) from c

Answer 11

你可以使用 ROLLUP

select nvl(name, 'SUM'), count(*)
from table
group by rollup(name)

Answer 12

用作

select Name, count(Name) as Count from YourTable
group by Name
union 
Select 'SUM' , COUNT(Name) from YourTable

Answer 13

我正在使用 SQL Server，以下应该适合你：

选择 cast(name as varchar(16)) as 'Name', count(name) as 'Count' from Table1 group by Name union all select 'Sum:', count(name) from Table1

Answer 14

我还需要having count(*) > 1 。 所以，在参考了上面的一些查询之后，我写了自己的查询

句法：

select sum(count) from (select count(`table_name`.`id`) as `count` from `table_name` where {some condition} group by {some_column} having count(`table_name`.`id`) > 1) as `tmp`;

例子：

select sum(count) from (select count(`table_name`.`id`) as `count` from `table_name` where `table_name`.`name` IS NOT NULL and `table_name`.`name` != '' group by `table_name`.`name` having count(`table_name`.`id`) > 1) as `tmp`;

Answer 15

您可以尝试按名称分组并计算该组中的 ID。

SELECT name, count(id) as COUNT FROM table group by name

Answer 16

查询后，运行下面得到总行数

select @@ROWCOUNT

Answer 17

select sum from (select count(Col_name) as s from Tab_name group by Col_name having count(*)>1)c