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c#将锯齿状数组复制到字符串

[英]c# Copying jagged arrays to strings

我的函数应该用“&”“;”分割字符串 和“,”并返回一个三重锯齿数组,反之亦然。 (根据数据:1,2,3; 4,5,6&1,2,3; 4,5,6)

我一直在努力使其工作,现在由于某种原因我正在获得一个系统.argumentnullexception on

Array.Copy(playerOneEnts, allEnts[0], playerOneEnts.Length);
Array.Copy(playerTwoEnts, allEnts[1], playerTwoEnts.Length);

完整代码:

public string convertToString(string[][][] allEnts)
{
    string Player = string.Empty;
    string[][] playerOneEnts = new string[maxEnts][];
    string[][] playerTwoEnts = new string[maxEnts][];

    Array.Copy(allEnts[0], playerOneEnts, allEnts[0].Length);
    Array.Copy(allEnts[1], playerTwoEnts, allEnts[1].Length);

    for (int j = 0; j < playerOneEnts.Length; j++)
    {
        for (int i = 0; i < playerOneEnts[j].Length; i++)
        {
            Player += playerOneEnts[j][i] + ",";
        }

        Player = Player.TrimEnd(',');
        Player += ";";
    }

    Player = Player.TrimEnd(';');
    Player += "&";

    for (int j = 0; j < playerTwoEnts.Length; j++)
    {
        for (int i = 0; i < playerTwoEnts[j].Length; i++)
        {
            Player += playerTwoEnts[j][i] + ",";
        }

        Player = Player.TrimEnd(',');
        Player += ";";
    }

    Player = Player.TrimEnd(';');
    return Player;
}

public string[][][] convertToArray(string ents)
{
    string[] p = new string[2];
    string[][] playerOneEnts = new string[maxEnts][];
    string[][] playerTwoEnts = new string[maxEnts][];
    string[][][] allEnts = new string[2][][];

    p = ents.Split('&');

    try
    {
        playerOneEnts = p[0].Split(new[] { ";" }, StringSplitOptions.RemoveEmptyEntries).Select(chunk => chunk.Split(',')).ToArray();
        playerTwoEnts = p[1].Split(new[] { ";" }, StringSplitOptions.RemoveEmptyEntries).Select(chunk => chunk.Split(',')).ToArray();

        MessageBox.Show(playerOneEnts.Length.ToString());

        Array.Copy(playerOneEnts, allEnts[0], playerOneEnts.Length);
        Array.Copy(playerTwoEnts, allEnts[1], playerTwoEnts.Length);
    }
    catch
    {
        MessageBox.Show("unable to convert string", "Fatal Error");
    }

    return allEnts;
}

该代码对我来说就像一场灾难,如果有人知道一种更好的方法将其转换为字符串,我会为任何想法感到高兴。 摆脱我的错误会帮助我足够。

谢谢!

这是使用Linq的示例(需要.Net 4.0):

var source = "1,2,3;4,5,6&1,2,3;4,5,6";

string[][][] decoded = source.Split('&').Select(x => x.Split(';').Select(y => y.Split(',').ToArray()).ToArray()).ToArray();

string reencoded = String.Join("&", decoded.Select(x => String.Join(";", x.Select(y => String.Join(",", y)))));

另外,可以使用IEnumarable泛型来避免转换为数组。

警告:此代码无法验证输入,例如数组长度。

编辑: .NET 3.5的重新编码器:

var reencoded = String.Join("&", decoded.Select(x => String.Join(";", x.Select(y => String.Join(",", y)).ToArray())).ToArray());

您可以使用嵌套的for循环来做到这一点:

string p = "1,2,3;4,5,6&1,5,3;4,5,9";
List<List<List<string>>> result = new List<List<List<string>>>();
foreach (var a in p.Split('&'))
{
    List<List<string>> level2 = new List<List<string>>();
    foreach (var b in a.Split(';'))
    {
        level2.Add(new List<string>(b.Split(',')));
    }
    result.Add(level2);
}
var x = result[0][1][2]; // This will result in '6'.

编码类似:

string encoded;
List<string> dec1 = new List<string>();
foreach (var a in result)
{
    string e = "";
    List<string> z = new List<string>();
    foreach (var b in a)
    {
        z.Add(String.Join(",", b));
    }
    e = String.Join(";", z);
    dec1.Add(e);
}
encoded = String.Join("&", dec1);

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