[英]networkx subgraph as node
我想替换一个子图S
一个networkx图的G
由单个节点N
一遍包含整个子图S
。 我需要这样做,因为我需要从N
到图形其他节点的边。
因为我没有使网络x的子图方法起作用,所以我编写了自己的代码来做到这一点。 但是我对结果感到困惑。
这是一个小的示例脚本:
import networkx as nx
from copy import deepcopy
from collections import deque
class XGraph(nx.MultiDiGraph):
def dographthings(self, graph_edges, graph_nodes, subgraph_nodes):
self.add_edges_from(graph_edges)
subgraph = deepcopy(self)
# remove all nodes and their transitive children from subgraph,that are
# not in subgraph_nodes
remove_subtree(deque((set(graph_nodes) - set(subgraph_nodes))), subgraph)
# remove all nodes from self that are now in subgraph
self.remove_nodes_from(subgraph)
print "subgraph:"
print type(subgraph)
for node in subgraph.nodes_iter():
print node
print "self:"
print type(self)
for node in self.nodes_iter():
print node
self.add_node(subgraph)
print self.node[subgraph]
def remove_subtree(nodes, graph):
"""
Removes all nodes that are successors of the nodes in ``nodes``.
Is robust for cyclic graphs.
Parameters
----------
graph : referance to networkx.graph
graph to remove nodes from
nodes : deque of nodes-ids
the nodes the successors of which to remove from graph
"""
to_remove = set()
to_add = list()
for node in nodes:
to_remove.add(node)
if node in graph:
to_add.extend(graph.successors(node))
graph.remove_node(node)
for node in to_remove:
nodes.remove(node)
for node in to_add:
nodes.append(node)
if len(nodes) > 0:
graph = remove_subtree(nodes, graph)
g = XGraph()
g.dographthings([(1,2),(2,3),(2,4),(1,5)], [1,2,3,4,5], [3,2,1])
XGraph
类具有一种将边添加到图形并如上所述构建子图的方法。 然后,当我遍历图和子图的节点时,一切似乎都是正确的。 然后,当我将子图添加为节点,并通过get_item-method访问它时,它似乎已经变成一个空字典,而不是MultiDiGraph,就像添加它作为节点之前一样。
脚本的输出是这样的:
subgraph:
<class '__main__.XGraph'>
1
2
3
self:
<class '__main__.XGraph'>
4
5
{}
为什么我的子图在添加为节点后变成字典,其所有数据都流向何处?
我错误地访问了该节点。 这样做是可行的:
for node in self.nodes_iter(data=True):
if isinstance(node[0], nx.MultiDiGraph):
print "this is the subgraph-node:"
print node
print "these are its internal nodes:"
for x in node[0].nodes_iter():
print x
else:
print "this is an atomic node:"
print node
输出:
this is the subgraph-node:
(<__main__.XGraph object at 0xb5ec21ac>, {})
these are its internal nodes:
1
2
3
this is an atomic node:
(4, {})
this is an atomic node:
(5, {})
我不太明白为什么您的代码无法正常工作。 这是一个小例子,可能会有所帮助
import networkx as nx
G = nx.Graph()
G.add_path([1,2,3,4])
S = G.subgraph([2,3]) # S is the graph 2-3
# add the subgraph as a node in the original graph
G.add_node(S)
# connect S to the neighbors of 2 and 3 and remove 2,3
for n in S:
nbrs = set(G.neighbors(n))
for nbr in nbrs - set([S]):
G.add_edge(S,nbr)
G.remove_node(n)
print(G.nodes()) # 1,4, <graph id>
print(G.edges()) # [(1, <graph id>), (<graph id>,4)]
我错误地访问了该节点。 这样做是可行的:
for node in self.nodes_iter(data=True):
if isinstance(node[0], nx.MultiDiGraph):
print "this is the subgraph-node:"
print node
print "these are its internal nodes:"
for x in node[0].nodes_iter():
print x
else:
print "this is an atomic node:"
print node
输出:
this is the subgraph-node:
(<__main__.XGraph object at 0xb5ec21ac>, {})
these are its internal nodes:
1
2
3
this is an atomic node:
(4, {})
this is an atomic node:
(5, {})
我有一个图G,首先将其划分为子图。然后创建一个新图A,并为其添加节点和边。 所以在这里我有多个子图,我想用一个节点替换这些子图,并在它们之间添加边。 在下面,分区是一个字典,它将图G的节点映射到该节点所属的社区。 首先,我将位于同一社区中的节点放入列表中,并从该节点创建一个子图。之后,找到列表的邻居并将边缘添加到新图中。
此代码可用于有向图或无向图。
A = nx.Graph()
commlist = []
for com in set(partition.values()) :
list_nodes = [nodes for nodes in partition.keys()if partition[nodes] == com]
commlist.append(list_nodes)
subgraph = G.subgraph(list_nodes)
A.add_node(com)
for node in list_nodes:
nbrs = set(G.neighbors(node))
for i in nbrs - set(list_nodes):
A.add_edge(com, G.node[i]['community'])
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