如何在字符串中查找重复单词的位置-Python

Question

如何使Python返回字符串中重复单词的位置？

例如，“猫坐在猫下面的垫子上”中的“猫”一词在句子的第2位和第11位。

Answer 1

您可以使用re.finditer查找字符串中所有出现的单词并以索引开头：

import re

for word in set(sentence.split()):
    indexes = [w.start() for w in re.finditer(word, sentence)]
    print(word, len(indexes), indexes)

并使用字典理解：

{word: [w.start() for w in re.finditer(word, sentence)] for word in sentence.split()}

Answer 2

这将返回一个字典，该字典将句子中的每个单词（至少重复一次）映射到单词索引（不是字符索引）列表

from collections import defaultdict

sentence = "the cat sat on the mat which was below the cat"

def foo(mystr):
    sentence = mystr.lower().split()
    counter = defaultdict(list)
    for i in range(len(sentence)):
        counter[sentence[i]].append(i+1)

    new_dict = {}
    for k, v in counter.iteritems():
        if len(v) > 1:
            new_dict[k] = v

    return new_dict

print foo(sentence)

Answer 3

下面的代码将输入一个句子，从该句子中取出一个单词，然后将其在列表中的位置打印，索引的起始索引为1（这就是您想要的代码）。

sentence = input("Enter a sentence, ").lower()
word = input("Enter a word from the sentence, ").lower()
words = sentence.split(' ')
positions = [ i+1 for i,w in enumerate(words) if w == word ]
print(positions)

Answer 4

我更喜欢简单，这是下面的代码：

sentence = input("Enter a sentence, ").lower()
word_to_find = input("Enter a word from the sentence, ").lower()
words = sentence.split()  ## Splits the string 'sentence' and returns a list of words in it. Split() method splits on default delimiters.

for pos in range(len(words)):
    if word_to_find == words[pos]:   ## words[pos] corresponds to the word present in the 'words' list at 'pos' index position.
        print (pos+1)

“单词”由句子中所有单词的列表组成。 然后在那之后，我们迭代并找到索引“ pos”中存在的每个单词与我们要查找的单词（word_to_find）匹配，如果两个单词都相同，则我们打印pos的值并添加1。

希望这对您来说足够简单，并且可以满足您的目的。

如果您希望对以上内容使用列表理解，则：

words = sentence.split()
positions = [ i+1 for i in range(len(words)) if word_to_find == words[i]]
print (positions)

上面的两种方法都是相同的，只是后面的方法会列出您的列表。

Answer 5

positions= [] 

sentence= input("Enter the sentence please: ").lower() 

sentence=sentence.split( ) 

length=len(sentence))

word = input("Enter the word that you would like to search for please: ").lower() 

if word not in sentence: 
     print ("Error, '"+word+"' is not in this sentence.") 

else: 
     for x in range(0,length):
          if sentence[x]==word: #
               positions.append(x+1)
     print(word,"is at positions", positions)

Answer 6

s="hello fattie i'm a fattie too"
#this code is unsure but manageable
looking word= "fattie"
li=[]
for i in range(len(s)):
    if s.startswith(lw, i):
        print (i)
        space = s[:i].count(" ")
        hello = space+1
        print (hello)
        li.append(hello)
print(li)