python编程时发生Elif错误

Question

# Get the input values.
b1 = input('Please enter the base.')
i1 = input('Please enter the index.')

# Define the funciton with parameter 'base' and 'index'.
def square(base, index):
    if base == 0:
        print('Can\'t calculate because base is equal to 0.')
    elif (not base == 0) and index == 0:
        print('The value is 0, because base is greater than 1, and index is equal to 0.')
    elif (not base == 0) and index == 1:
        print('The answer is equal to base, because index is equal to 1. Therefore, The answer is {ans}.'.format(ans=base))
    elif (not base == 0) and index == 2:
        print('{b} squared is {c}.'.format(b=base, c=(b ** 2))
    elif (not base == 0) and (index > 2 or index < 0):
        print('{b} to the power of {i} is equal to {c}'.format(b=base, i=index, c=base**index))

# Print the function.
print(square(b1, i1))

错误是这样的：

第36行，elif（not base == 0）和（index> 2 or index <0）：

SyntaxError：语法无效

我使用python 3.5.1。 如何解决此错误？

Answer 1

问题不在那条线上，而是在上面的那条线上。 您没有关闭足够的括号。 尝试在前一行的末尾添加另一个右括号。