Spring Boot + Apache CXF：为什么找不到wsdl？

Question

同事，我仍在尝试“结识所有人” Spring-Boot，Tomcat和Web服务实现类：

@javax.jws.WebService(
                      serviceName = "ServiceForApp",
                      portName = "ServiceEndPoind",
                      targetNamespace = "http://new.webservice.namespace",
                      endpointInterface = "com.comp.appserv.WebServiceInterface",
                          wsdlLocation = "resources/WebService.wsdl"
                          )

public class ServiceEndPoindImpl implements WebServiceInterface {logic};

我有一个应用程序类：

package com.comp.config;


import org.apache.cxf.Bus;
import org.apache.cxf.bus.spring.SpringBus;
import org.apache.cxf.jaxws.EndpointImpl;
import org.apache.cxf.transport.servlet.CXFServlet;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.SpringApplication;

import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.context.embedded.ServletRegistrationBean;
import org.springframework.context.ApplicationContext;
import org.springframework.context.annotation.Bean;
import com.comp.appserv.ServiceEndPoindImpl;

import javax.xml.ws.Endpoint;


@SpringBootApplication
public class Application  {

    public static final String SERVLET_MAPPING_URL_PATH = "/soap/*";
    public static final String SERVICE_NAME_URL_PATH = "/app";

    @Autowired
    private ApplicationContext applicationContext;

    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }

    @Bean
    public ServletRegistrationBean dispatcherServlet() {
        return new ServletRegistrationBean(new CXFServlet(), SERVLET_MAPPING_URL_PATH);
    }


    @Bean(name = Bus.DEFAULT_BUS_ID)
    // <bean id="cxf" class="org.apache.cxf.bus.spring.SpringBus">
    public SpringBus springBus() {
        return new SpringBus();
    }

    @Bean
    // <jaxws:endpoint id="app" implementor="com.dlizarra.app.ws.AppImpl" address="/app">
    public Endpoint app() {
        Bus bus = (Bus) applicationContext.getBean(Bus.DEFAULT_BUS_ID);
        Object implementor = new ServiceEndPoindImpl();
        EndpointImpl endpoint = new EndpointImpl(bus, implementor);
        endpoint.publish(SERVICE_NAME_URL_PATH);
        return endpoint;
    }
}

我的目标是获得带有嵌入式Tomcat和Web服务的单个jar文件。 当前我的问题是在mvn spring-boot:run我收到异常

Caused by: java.io.FileNotFoundException: C:\Users\Maya\git\web-services\resources\WebService.wsdl (The system cannot find the file specified)
        at java.io.FileInputStream.open0(Native Method)
        at java.io.FileInputStream.open(FileInputStream.java:195)
        at java.io.FileInputStream.<init>(FileInputStream.java:138)
        at java.io.FileInputStream.<init>(FileInputStream.java:93)
        at sun.net.www.protocol.file.FileURLConnection.connect(FileURLConnection.java:90)
        at sun.net.www.protocol.file.FileURLConnection.getInputStream(FileURLConnection.java:188)


The full stacktrace is here: http://pastebin.com/Ez3S5CWu

您能否为我提供下一个问题的答案：

1. 为什么Spring尝试通过此链接C:\\Users\\Maya\\git\\web-services\\resources\\WebService.wsdl来找到wsdl，而不是从@javax.jws.WebService批注的路径中找到？ 我应该在哪里设置此路径？

2. 用嵌入式Tomcat创建单个jar是否正确？

Answer 1

春天是使用从标注的路径; 但由于它是相对路径，因此使用当前目录（您的应用程序从rom启动）。

尝试

wsdlLocation = "classpath:resources/WebService.wsdl"

在类路径中搜索。

至于问题2，只要没有阻止它的方法，从头开始是正确的方法吗？ 您的IT基础结构可能由于某些原因而否决了它。