![](/img/trans.png)
[英]Apache CXF(with spring boot) How can I return original WSDL file(not generated by cxf)?
[英]Spring Boot + Apache CXF: why can't find wsdl?
同事,我仍在嘗試“結識所有人” Spring-Boot,Tomcat和Web服務實現類:
@javax.jws.WebService(
serviceName = "ServiceForApp",
portName = "ServiceEndPoind",
targetNamespace = "http://new.webservice.namespace",
endpointInterface = "com.comp.appserv.WebServiceInterface",
wsdlLocation = "resources/WebService.wsdl"
)
public class ServiceEndPoindImpl implements WebServiceInterface {logic};
我有一個應用程序類:
package com.comp.config;
import org.apache.cxf.Bus;
import org.apache.cxf.bus.spring.SpringBus;
import org.apache.cxf.jaxws.EndpointImpl;
import org.apache.cxf.transport.servlet.CXFServlet;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.context.embedded.ServletRegistrationBean;
import org.springframework.context.ApplicationContext;
import org.springframework.context.annotation.Bean;
import com.comp.appserv.ServiceEndPoindImpl;
import javax.xml.ws.Endpoint;
@SpringBootApplication
public class Application {
public static final String SERVLET_MAPPING_URL_PATH = "/soap/*";
public static final String SERVICE_NAME_URL_PATH = "/app";
@Autowired
private ApplicationContext applicationContext;
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
@Bean
public ServletRegistrationBean dispatcherServlet() {
return new ServletRegistrationBean(new CXFServlet(), SERVLET_MAPPING_URL_PATH);
}
@Bean(name = Bus.DEFAULT_BUS_ID)
// <bean id="cxf" class="org.apache.cxf.bus.spring.SpringBus">
public SpringBus springBus() {
return new SpringBus();
}
@Bean
// <jaxws:endpoint id="app" implementor="com.dlizarra.app.ws.AppImpl" address="/app">
public Endpoint app() {
Bus bus = (Bus) applicationContext.getBean(Bus.DEFAULT_BUS_ID);
Object implementor = new ServiceEndPoindImpl();
EndpointImpl endpoint = new EndpointImpl(bus, implementor);
endpoint.publish(SERVICE_NAME_URL_PATH);
return endpoint;
}
}
我的目標是獲得帶有嵌入式Tomcat和Web服務的單個jar文件。 當前我的問題是在mvn spring-boot:run
我收到異常
Caused by: java.io.FileNotFoundException: C:\Users\Maya\git\web-services\resources\WebService.wsdl (The system cannot find the file specified)
at java.io.FileInputStream.open0(Native Method)
at java.io.FileInputStream.open(FileInputStream.java:195)
at java.io.FileInputStream.<init>(FileInputStream.java:138)
at java.io.FileInputStream.<init>(FileInputStream.java:93)
at sun.net.www.protocol.file.FileURLConnection.connect(FileURLConnection.java:90)
at sun.net.www.protocol.file.FileURLConnection.getInputStream(FileURLConnection.java:188)
The full stacktrace is here: http://pastebin.com/Ez3S5CWu
您能否為我提供下一個問題的答案:
為什么Spring嘗試通過此鏈接C:\\Users\\Maya\\git\\web-services\\resources\\WebService.wsdl
來找到wsdl,而不是從@javax.jws.WebService
批注的路徑中找到? 我應該在哪里設置此路徑?
用嵌入式Tomcat創建單個jar是否正確?
春天是使用從標注的路徑; 但由於它是相對路徑,因此使用當前目錄(您的應用程序從rom啟動)。
嘗試
wsdlLocation = "classpath:resources/WebService.wsdl"
在類路徑中搜索。
至於問題2,只要沒有阻止它的方法,從頭開始是正確的方法嗎? 您的IT基礎結構可能由於某些原因而否決了它。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.