python如何按digit = string排序字符串列表

Question

如何对以下python列表进行排序

nlist = [
"494=Deploy\00000001.inx",
"19=Deploy\0000000144.exe",
"2=Deploy\00000001_index.dat",
"9=Deploy\0000001b_index.bin",
"1=Deploy\00000001_index.bin",
"7=Deploy\00000019_index.bin",
"2=Deploy\00000001_Onedata.dat",
"19=Deploy\000000024444.exe"
] 

跟随

sortedList = [
"1=Deploy\00000001_index.bin",
"2=Deploy\00000001_index.dat",
"2=Deploy\00000001_Onedata.dat",
"7=Deploy\00000019_index.bin",
"9=Deploy\0000001b_index.bin",
"19=Deploy\0000000144.exe",
"19=Deploy\000000024444.exe",
"494=Deploy\00000001.inx",
] 

有可能使它成为单衬里吗

Answer 1

对列表进行排序，并传递一个键，该键将'='上的列表中的字符串分割开并选择数字部分， nlist.sort修改原始列表，如果您想要一个新列表，最好使用sorted()

nlist.sort(key=lambda x: int(x.split('=')[0]))
print(nlist)

产量

['1=Deploy\x0000001_index.bin', '2=Deploy\x0000001_index.dat', '2=Deploy\x0000001_Onedata.dat', '7=Deploy\x0000019_index.bin', '9=Deploy\x000001b_index.bin', '19=Deploy\x000000144.exe', '19=Deploy\x00000024444.exe', '494=Deploy\x0000001.inx']