如何通过正则表达式获取字符串中所有不匹配的范围？

Question

我有一个正则表达式和一个字符串。 我需要找到字符串中所有不匹配的内容都是正则表达式，并获取字符串中的范围。 我怎样才能做到这一点？

#include <regex>
#include <string>
#include <iostream>

void printNonMatches(const std::regex& re, const std::string& str) {
    const std::string& part;
    size_t start;
    size_t end;

    /* get next non-match */
    /* std::cout << part << " : " << start << ", " << end << std::endl; */
}

Answer 1

解：

#include <string>
#include <iostream>
#include <regex>

void printNonMatches(const std::regex& r, const std::string& s) {
    size_t lastEndPosition = 0;

    for (std::sregex_iterator i = std::sregex_iterator(s.begin(), s.end(), r); i != std::sregex_iterator(); ++i) {
        std::smatch m = *i;

        std::cout << s.substr(lastEndPosition, m.position() - lastEndPosition) << " : " << lastEndPosition << ", " << m.position() << std::endl;
        lastEndPosition = m.position() + m.length();
    }
    if (lastEndPosition != s.length())
        std::cout << s.substr(lastEndPosition, s.length() - lastEndPosition) << " : " << lastEndPosition << ", " << s.length()  << std::endl;
}

int main() {
    std::string s = "My new string";
    std::regex r("\\s+");
    printNonMatches(r, s);
    return 0;
}

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