[英]how to get request HTTP headers in soaplib views file?
我有用于webservice的soaplib作为soap [server],所有请求路由和响应都通过url好了。但是我无法获取请求的HTTP标头,如何获取请求的HTTP标头来呈现视图类的某些方法?
像这种方法:
def redirect_http(self,request):
return render(request, 'ask/redirect.html', {
''' 'question': question,
'error_message': "You didn't select a choice.", '''
})
代码项目:
soap.py
'''
documentation in http://soaplib.github.com/soaplib/2_0/
'''
import base64
import soaplib
from soaplib.core import Application
from soaplib.core.model import primitive as soap_types
from soaplib.core.service import DefinitionBase
from soaplib.core.service import rpc as soapmethod
from soaplib.core.server import wsgi
from soaplib.core.model.clazz import ClassModel
from soaplib.core.model.clazz import Array
from django.http import HttpResponse
# the class with actual web methods
# the class which acts as a wrapper between soaplib WSGI functionality and Django
class DjangoSoapApp(wsgi.Application):
def __call__(self, request):
# wrap the soaplib response into a Django response object
django_response = HttpResponse()
def start_response(status, headers):
status, reason = status.split(' ', 1)
django_response.status_code = int(status)
for header, value in headers:
django_response[header] = value
response = super(DjangoSoapApp, self).__call__(request.META, start_response)
django_response.content = '\n'.join(response)
return django_response
class SoapView(DefinitionBase):
@classmethod
def as_view(cls):
soap_application = Application([cls], __name__)
return DjangoSoapApp(soap_application)
# the view to use in urls.py
#my_soap_service = DjangoSoapApp([MySOAPService], __name__)
views.py
from soap import SoapView
from soap import soapmethod
from soap import soap_types, Array
class MySoapService(SoapView):
__tns__ = '[url]http://localhost:8989/api/soap/verify.wsdl[/url]'
@soapmethod(soap_types.String, soap_types.Integer, returns=soap_types.String)
def request_verify(self, q, id, uri):
#Some Code
return 'some return'
my_soap_service = MySoapService.as_view()
urls.py
from django.conf.urls import patterns, include, url
from django.views.generic import RedirectView
import views
# Main URL Patterns
urlpatterns = [
url(r'^verify', views.my_soap_service),
url(r'^verify.wsdl', views.my_soap_service),
]
解决的问题:更改方法请求(用于生成html并获取http头,最遵守协议的HTTP和结构),因此要请求和响应html内容应发送http请求并获取所有头
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