[英]preg_match extract identifier and alias
我正在尝试从mysql ORDER BY中提取标识符和别名,最近的问题可以帮助我的问题是,使用C#和正则表达式从SQL select语句中删除别名
function test($orderby)
{
if(preg_match('/(?<field>.*)(?:\s*|\s+AS\s+)?(?<alias>\w*)?/i', $orderby, $matches)){
unset($matches[1]);
unset($matches[2]);
echo '<pre>'.htmlspecialchars(print_r($matches,true)).'</pre>';
}else{
echo '$orderby doest not matches';
}
}
test("field");
作品
Array
(
[0] => field
[field] => field
[alias] =>
)
test("table.field");
作品
Array
(
[0] => table.field
[field] => table.field
[alias] =>
)
test("CONCAT(table.field1, ' ', table.field2) AS alias");
不起作用
Array
(
[0] => CONCAT(table.field1, ' ', table.field2) AS alias
[field] => CONCAT(table.field1, ' ', table.field2) AS alias
[alias] =>
)
test("table.field alias");
版画
Array
(
[0] => table.field alias
[field] => table.field alias
[alias] =>
)
我需要在示例3 [field] => CONCAT(table.field1, ' ', table.field2)
和[alias] => alias
,在示例4中需要[field] => table.field
AND [alias] => alias
我想做的是
/
(?<field>.*) #identifier
(?:\s*|\s+AS\s+)? # without spaces (examples 1 and 2), spaces (example 4) OR 'AS' (example 3)
(?<alias>\w*)? #alias
/i
我做错了什么? 提前致谢。
此模式适用于所有示例:
/(?<field>.*?)((?:\s+|\s+AS\s+)(?<alias>\w+))?$/i
│ │ │ ┊ │ │┊│
1 2 3 4 5 267
1) Added not-greedy operator;
2) Added capturing group for sub-groups AS/alias;
3) Changed zero-or-more to one-or-more (at least one space is needed);
4) Removed zero-or-one for subgroup AS (at least one space is needed);
5) Changed zero-or-more to one-or-more (at least one char is needed);
6) Moved zero-or-more from sub-group alias to group 2);
7) Added end-of-line anchor.
创建了新的捕获组,因此您还必须取消设置$matches[3]
:
unset( $matches[1], $matches[2], $matches[3] );
由于我们添加了终点锚,因此建议您在函数开头添加以下行:
$orderby = trim( $orderby );
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